A^3
a to the power of three
Can you crop a better photo of the question please
<span>2x^2 - 19x - 33 = 0 </span>
<span>The factors of 2 are 1 x 2. </span>
<span>The factors of 33 are 1 x 33 and 3 x 11. </span>
<span>Using Guess and Test and FOIL, find a combination that gives you a middle term of -19x: </span>
<span>(2x + 3)(x - 11) = 0. </span>
<span>Using the principal of zero product, solve each equation for x: </span>
<span>2x + 3 =0 and x - 11 =0. </span>
<span>The two solutions are x = -3/2 and x = 11.
</span>
Answer:
250
Step-by-step explanation:
All you have to do to go from L to mL is x1000
