Answer:
<u>There are:</u>
- 6 red balls - R
- 5 black balls - B
- Total number = 11 balls
<h3>A. Without replacement</h3>
i. <u>Two blacks </u>
ii. <u>The first is black</u>
or, alternatively
- P(BR or BB) = 5/11*6/10 + 2/11 = 3/11 + 2/11 = 5/11
iii. <u>Both are of same colour</u>
- P(BB or RR) = 2/11 + 6/11*5/10 = 2/11 + 3/11 = 5/11
<h3>B. With replacement</h3>
i. <u>Two blacks </u>
- P(BB) = 5/11*5/11 = 25/121
ii. <u>The first is black</u>
or alternatively
- P(BR or BB) = 5/11*6/11 + 25/121 = 30/121 + 25/121 = 55/121 = 5/11
iii. <u>Both are of same colour</u>
- P(BB or RR) = 5/11*5/11 + 6/11*6/11 = 25/121 + 36/121 = 61/121
Answer:
The unit rate is 
Step-by-step explanation:
Given : Kenny reads 
page in 
min.
To find : What is Kenny's unit rate?
Solution :
Kenny reads page in minute
This can be written as,
Divide both side by 
The unit rate is
Answer:
The length of DF must be between 21 and 53.
Step-by-step explanation:
In a triangle, the length of two sides added together must exceed the length of the 3rd side. So, since EF is the shortest of the two givens, we know that EF + DF must be greater than DE. So we can plug in these numbers to find the minimum.
EF + DF > DE
16 + DF > 37
DF > 21
Now, for the upper maximum, we know that the two given lengths must be greater than the length of DF. So again, we can solve for the maximum using the amounts.
DE + EF > DF
37 + 16 > DF
53 > DF
With these two in mind, we know that DF must be between 21 and 53
3/11 is the simplified version of this fraction
We are given with two equations to find the values of two variables, hence the problem can be solved.
Adding the two equations:
x + y = 12<u>x - y = 10
</u>2x = 22
<u />x =11
y = 1
