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Sidana [21]
3 years ago
9

18)

Mathematics
2 answers:
SpyIntel [72]3 years ago
8 0

Step-by-step explanation:

18 \frac{1}{2}  \times ( \frac{1}{4} )

\frac{37}{2}  \times  \frac{1}{4}

\frac{37}{8}

4 \frac{5}{8}

alexandr402 [8]3 years ago
6 0
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Janani ran for 60 minutes and traveled 5 miles. What is her rate per mile?
Diano4ka-milaya [45]

Answer:

6.67 miles per hour

Step-by-step explanation: Im 97.99% sure this is right!! :)

6 0
2 years ago
A biologist is studying a certain type of algae. She starts with only 1 algae bloom and observes that the number of algae blooms
attashe74 [19]

Answer:

h = \log_{3}{a_h}

Step-by-step explanation:

The formula for the nth term of a geometric sequence is

a_{n} = a_{1}r^{n-1}

a₀ = 1, r = 3, and n = h

So,

a_{h} = 3^{h}

h = \log_{3}{a_h}

h = \log_{3}{6561} = 8

6 0
3 years ago
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$1,200 TV; discount 40%
aev [14]
Answer: $480

Explanation: First, change the percentage to a decimal by dividing by 100. 40/100 = .4
Then multiply .4 by the cost, $1200. .4*1200 = $480
4 0
4 years ago
The spherical balloon is inflated at the rate of 10 m³/sec. Find the rate at which the surface area is increasing when the radiu
rjkz [21]

The balloon has a volume V dependent on its radius r:

V(r)=\dfrac43\pi r^3

Differentiating with respect to time t gives

\dfrac{\mathrm dV}{\mathrm dt}=4\pi r^2\dfrac{\mathrm dr}{\mathrm dt}

If the volume is increasing at a rate of 10 cubic m/s, then at the moment the radius is 3 m, it is increasing at a rate of

10\dfrac{\mathrm m^3}{\mathrm s}=4\pi (3\,\mathrm m)^2\dfrac{\mathrm dr}{\mathrm dt}\implies\dfrac{\mathrm dr}{\mathrm dt}=\dfrac5{18\pi}\dfrac{\rm m}{\rm s}

The surface area of the balloon is

S(r)=4\pi r^2

and differentiating gives

\dfrac{\mathrm dS}{\mathrm dt}=8\pi r\dfrac{\mathrm dr}{\mathrm dt}

so that at the moment the radius is 3 m, its area is increasing at a rate of

\dfrac{\mathrm dS}{\mathrm dt}=8\pi(3\,\mathrm m)\left(\dfrac5{18\pi}\dfrac{\rm m}{\rm s}\right)=\dfrac{20}3\dfrac{\mathrm m^2}{\rm s}

4 0
3 years ago
In 2012, Indonesia experienced an intense earthquake with a magnitude of 8.6 on the Richter scale. In 1952, Uganda experienced a
Katyanochek1 [597]

Answer:

The intensity of the 2012 earthquake was about 126 times the intensity of the 1952 earthquake.

Step-by-step explanation:

To compare the intensities, we first need to convert the magnitudes to intensities using the log formula. Then we will set up a ratio to compare the intensities.

Convert the magnitudes to intensities and convert to exponential form.

R=logI

2012 earthquake:

8.6I=logI=108.6

1952 earthquake:

6.5I=logI=106.5

Form a ratio of the intensities.

intensity for 2012intensity for 1952

Substitute in the values and divide by subtracting the exponents to find

108.6106.5102.1≈126.

The intensity of the 2012 earthquake was about 126 times the intensity of the 1952 earthquake.

Your answer:

The intensity of the 1952 earthquake was about 110 times the intensity of the 2012 earthquake.

6 0
3 years ago
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