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wel
3 years ago
8

Factor completely 4x4 − 24x3 + 36x2.

Mathematics
2 answers:
lorasvet [3.4K]3 years ago
6 0

Answer:

The correct option is 1.

Step-by-step explanation:

The given expression is

4x^4-24x^3+36x^2

Taking out the greatest common factor.

4x^2(x^2-6x+9)

4x^2(x^2-3x-3x+9)

4x^2(x(x-3)-3(x-3))

4x^2(x-3)(x-3)

4x^2(x-3)^2

The complete factor form of the given expression is 4x^2(x-3)^2.

Therefore the correct option is 1.

ehidna [41]3 years ago
3 0
Factor out 4x² from everybody
4x²(x²-6x+9)
factor inner
what 2 numbers multipliy to gete 9 and add to get -6
-3 and -3
4x²(x-3)(x-3)
or
4x²(x-3)²


first option
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Part 1) \frac{a^4}{4b^2}

Part 2) -\frac{v^9}{w^6}

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6 0
3 years ago
There are 3 bags each containing 100 marbles. Bag 1 has 75 red and 25 blue marbles. Bag 2 has 60 red and 40 blue marbles. Bag 3
jekas [21]

Answer:

0.4 ; 0.6125

Step-by-step explanation:

Given the following :

Bag 1 : 75 red ; 25 blue

Bag 2: 60 red ; 40 blue

Bag 3: 45 red ; 55 blue

Probability = (required outcome / Total possible outcomes)

A) since the probability of choosing each bag is equal :

BAG A:

P(choosing bag A) = 1 / total number of bags = 1/3 ; P(choosing blue marble) = number of blue marbles / total number of marbles = 25/100

HENCE, choosing a blue marble from bag A : = (1/3 × 75/100) = 25/300

BAG B:

P(choosing bag B) = 1/3 ;

P(choosing blue marble) = number of blue marbles / total number of marbles = 40/100

HENCE, choosing a blue marble from bag A : = (1/3 × 40/100) = 40/300

BAG C:

P(choosing bag C) = 1/3

P(choosing blue marble) = number of blue marbles / total number of marbles = 55/100

HENCE, choosing a blue marble from bag A : = (1/3 × 55/100) = 55/300

= (25/300) × (40/300) × (55/300) = (25 + 40 + 55)/300 = 120/300 = 0.4

2) What is the probability that the marble is blue when the first bag is chosen with probability 0.5 and other bags with equal probability each?

BAG A:

P(choosing bag A) = 0.5 ; P(choosing blue marble) = number of blue marbles / total number of marbles = 25/100

HENCE, choosing a blue marble from bag A : = (0.5 × 75/100) = (0.5 * 0.75) = 0.375

BAG B:

P(choosing bag B) = (1-0.5) / 2 = 0.25 ;

P(choosing blue marble) = number of blue marbles / total number of marbles = 40/100

HENCE, choosing a blue marble from bag A : = (0.25 × 40/100) = (0.25 × 0.4) = 0.1

BAG C:

P(choosing bag C) = (1 - (0.5+0.25)) = 0.25

P(choosing blue marble) = number of blue marbles / total number of marbles = 55/100

HENCE, choosing a blue marble from bag A : = (0.25 × 55/100) = 0.25 × 0.55 = 0.1375

= 0.1375 + 0.1 + 0.375 = 0.6125

7 0
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