Question

a number is equal to twice a smaller number plus 3. The same number is equal to twice the sum of the smaller number and1. How many solutions?

Answer 1

Answer:

There is NO solution

Step-by-step explanation:

Considering 'y' be the number

Considering x be the smaller number

As 'y' is equal to twice a smaller number plus 3.

so

$y = 2x + 3$

also

y is equal to twice the sum of the smaller number and 1.

so

$y = 2x + 1$

so the system of equations become

$y = 2x + 3$

$y = 2x + 1$

solving

$\begin{bmatrix}y=2x+3\\ y=2x+1\end{bmatrix}$

$\mathrm{Subsititute\:}y=2x+1$

$\begin{bmatrix}2x+1=2x+3\end{bmatrix}$

$\mathrm{Refine\:}2x+1=2x+3$

$-2=0$

$-2=0\:\mathrm{\:is\:false,\:therefore\:the\:system\:of\:equations\:has\:no\:solution}$

$\mathrm{No\:Solution}$

Therefore, there is NO solution.