28 men are needed to paint the room in 3 hours
<h3><u>Solution:</u></h3>
Given that it takes 12 hours for 7 men to paint a room
We are asked to find number of men required to paint the room in 3 hours
Recognize, "paint the room" is 1 task. One job.
7 men -------- 12 hours ------ 1 job
(7/7) = 1 men ------- 12 x 7 (84) ------- same 1 job
The one men is rate is 84 hours to do the job
We can express this as 1/84 jobs per hour, the one-person rate
Now lets find how many men needed to paint the room in 3 hours
Let the required number of men for 3 hours be "a"
The rates of each person is simply additive.
corresponds to rate x hours = jobs and "a" is a variable for how many men
Thus 28 men are needed to paint the room in 3 hours
Answer:
525 x 1,050
A = 551,250 m²
Step-by-step explanation:
Let 'L' be the length parallel to the river and 'S' be the length of each of the other two sides.
The length of the three sides is given by:
The area of the rectangular plot is given by:
The value of 'S' for which the area's derivate is zero, yields the maximum total area:
Solving for 'L':
The largest area enclosed is given by dimension of 525 m x 1,050 and is:
Answer:
f(4) =2
Step-by-step explanation:
f(x) = 2х^2 - 30,
Let x=4
f(4) = 2 (4)^2 -30
= 2*16 -30
=32-30
= 2
Answer:
cos 45 degree = A/H
cos 45 degree = 2 square root 2 / x
x = 2 square root 2 / cos 45 degree
x = 4
Sin 45 degree = O/H
Sin 45 degree = y/ 4
4 x Sin 45 degree = y
y = 2.83
or
we could use tan
tan 45 degree = O/A
tan 45 degree = y / 2 square root 2
2 square root 2 x tan 45 degree = y
y = 2.83
i hope this would elp a little bit.