One letter is selected from the word "probability." What is the probability that a "b" or "i" is chosen?
2 answers:
<u>Answer:</u>
The correct answer option is 4/11
<u>Step-by-step explanation:</u>
We know that the word 'probability' has 11 alphabets.
We are to find to find the probability of getting a 'b' or an 'i' from this word.
Probability of getting a b =
(since there are 2 b's in probability)
Probability of getting an i =
(since there are 2 i's in probability)
Probability of getting 'b' or 'i' = 
4/11
First, count how many letters are in “probability”. There are 11 letters.
Now, count how many b’s there are in the word. There are 2.
Then, count how many i’s are in the word. There are also 2.
Add the b’s and i’s together to find that there are 4 of them.
There are 4 possible ways to choose a “b” or an “i”, and there are 11 possible letters to choose from. So, the probability is 4/11.
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Answer: 2r=d
d=24.28590063
Step-by-step explanation:
vsphere=4/3pir^3
7500=4/3pir^3
times both sides by 3
22500=4pir^3
divide both sides by 4
5625=pir^3
divide bot sides by pi
1790.4931=r^3
cube root both sides
12.142950=r
2r=d
d=24.28590063 ft