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sdas [7]
3 years ago
9

PLEASE HELP!!!! WILL GIVE BRAINLIEST!!!

Mathematics
1 answer:
Natasha2012 [34]3 years ago
4 0

Use Ga_thMath(u) (brainly doesn't allow me to type it) To use the app u need to take a pic of the problem and then it will process it and you'll get ur answer ASAP(most of the time). Many questions have been asked before so search it on brainly.

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Find the distance between line 11x-60y-15=0 and point (2, 1/60)
vovikov84 [41]

Answer:

The answer to your question is: d = 6 / 61 or 0.1 units

Step-by-step explanation:

Data

Line: 11x - 60y - 15 = 0   A = 11; B = -60; C = -15

Point (2, 1/60)                 x = 2    y = 1/60

Formula

d = | Ax + By + C | / √(A² + B²)

Process

d = | (11)(2) + (-60)(1/60) -15 | / √(11² + (-60²)

d = | 22 -1 - 15 | / √ 121 + 3600

d = | 6 | / √3721

d = | 6 | / 61

d = 6 / 61 or 0.1 units

8 0
4 years ago
Read 2 more answers
Explain what a finite sequence might refer to.
Rom4ik [11]
Answer: A sequence of numbers that has an ending rather than no ending.

There are infinite sequences and finite sequences in mathematics.
3 0
3 years ago
Calculate the unpaid balance, finance charge, and new balance using the unpaid balance method. Note: interest rate is given as a
nata0808 [166]

Answer:

Unpaid balance = $56.96

Finance charge = $0.8544

New balance =$171.7944

Step-by-step explanation:

Given : Previous balance = $91.96

Payments/credits = $35.00

Monthly rate = 1.5%

New purchases = $113.98

To calculate : The unpaid balance, finance charge, and new balance using the unpaid balance method.  

Solution :  

Unpaid balance = Previous balance - Payments

Unpaid balance = $91.96- $35

Unpaid balance  = $56.96

We have given rate of interest= 1.5%=0.015

Finance charge = Finance rate × Unpaid balance

Finance charge = 0.015\times 56.96

Finance charge = $0.8544

New balance =  Unpaid balance + finance charge + new transaction

New balance =  $56.96 +$0.8544+ $113.98

New balance =$171.7944

6 0
3 years ago
if a rectangle has a greater perimeter than another rectangle, does it also have a greater area? Explain.
Lemur [1.5K]
No.

The maximum possible area given a constant amount of material for a quadrilateral will always be a square.

For example if the material for the perimeter is 64 we can form a rectangle that is 22 by 10 which will have an area of 220 u^2.

However a square using the same amount of material will have sides of 64/4=16 and an area of 16^2=250 u^2

So in general the area is maximize the closer the sides are to being equal and minimized as the difference between the sides becomes greater.  In the case of comparing the material, perimeter, of a rectangle to a square for the same amount of material the square will use less material than the rectangle.

A square can have a smaller perimeter and a greater area that a rectangle.

In the example above the rectangle had a perimeter of 64 u and an area of 220 u^2.  If we made a square with just 60 u, it would have an area of 225 u^2.
4 0
3 years ago
Tim has to cover 3 tanks completley with paint. ​
bija089 [108]

<em>answer:</em>

<h3><em>Total </em><em>surface </em><em>area </em><em>of </em><em>3</em><em> </em><em>tanks=</em><em>3</em><em>4</em><em>.</em><em>3</em><em> </em><em>m^</em><em>2</em></h3><h3><em>7</em><em> </em><em>tins </em><em>of </em><em>paint </em><em>are </em><em>required</em><em>.</em></h3>

<em>Solution</em><em>,</em>

<em>diameter </em><em>of </em><em>tank=</em><em>1</em><em>.</em><em>4</em><em> </em><em>m</em>

<em>Height </em><em>of </em><em>tank=</em><em>1</em><em>.</em><em>9</em><em> </em><em>m</em>

<em>Given </em><em>tank </em><em>has </em><em>top </em><em>and </em><em>bottom </em>

<em>Now,</em><em> </em><em>The </em><em>total </em><em>surface </em><em>area </em><em>of </em><em>cylinder </em><em>tank </em><em>is </em><em>given </em><em>by:</em>

<em>tsa = 2\pi \:  {r}^{2}  + (2\pi \: r \: ) \times h</em>

<em>r(</em><em> </em><em>radius </em><em>of </em><em>tank)</em><em>=</em>

<em>\frac{diameter}{2}  =  \frac{1.4}{2}  = 0.7 \: m</em>

<em>h(</em><em>height </em><em>of </em><em>tank)</em><em>=</em><em>1</em><em>.</em><em>9</em><em> </em><em>m</em>

<em>TSA </em><em>of </em><em>1</em><em> </em><em>tank</em>

<em>=</em>

<em>2 \times 3.14 \times  {(0.7)}^{2}  + 2 \times 3.14 \times 0.7 \times 1.9 \\  = 11.435 \:  {m}^{2}</em>

<em>TSA </em><em>Of </em><em>3</em><em> </em><em>tanks</em>

<em>=</em>

<em>3 \times 11.435 \:  {m}^{2}  \\  = 34.3 \:  {m}^{2}</em>

<em>Given </em><em>a </em><em>tin </em><em>of </em><em>plate </em><em>covers </em><em>5</em><em>m</em><em>^</em><em>2</em><em> </em><em>area.</em>

<em>No.of </em><em>tins </em><em>required:</em>

<em>1</em><em> </em><em>tin</em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>5</em><em>m</em><em>^</em><em>2</em>

<em>x </em><em>tin</em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>3</em><em>4</em><em>.</em><em>3</em><em> </em><em>m^</em><em>2</em>

<em>5x = 34.3(cross \: multiplication) \\ or \: x =  \frac{34.3}{5}  \\ x = 6.86 \\ x = 7 \: tins</em>

<em>there</em><em>fore</em><em> </em><em>7</em><em> </em><em>tins </em><em>are </em><em>required</em><em>.</em>

<em>Hope </em><em>this </em><em>helps.</em><em>.</em><em>.</em>

<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em><em>.</em>

8 0
3 years ago
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