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kolbaska11 [484]
3 years ago
12

Please help! What is the value of arcsin(−1/2) in degrees?

Mathematics
2 answers:
Nimfa-mama [501]3 years ago
7 0

Answer:

x = 210 and 330 degrees  where  0 =< x <= 360.

Step-by-step explanation:

The angles whose sine is -1/2 are 210 and 330 degrees for angles between 0 and 360 degrees.

The general results are 210 +/- 360  and 330 +/- 360 degrees.

stellarik [79]3 years ago
6 0

Answer:

-30 degrees

Step-by-step explanation:

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Carlos has 32 envelopes and wants to deliver 3 envelopes to each class. How many classrooms will he visit?
statuscvo [17]

10 classrooms

With 2 left over.

It's a simple question, make sure that you know that the key is 32/3, and because it's not fully divisible use the whole number (10)

8 0
3 years ago
In a right triangle, the hypotenuse is three inches more than twice the length of one leg. If the other leg is 12 inches, what i
andrew-mc [135]

Answer:

Length of hypothenuse = 13 inches

Length of other leg = 5 inches

Step-by-step explanation:

A triangle has three sides and three angles. A right angle triangle has 90 degrees as one of the angles. The remaining two angles are complimentary. This means that the sum if the other two angles is 90 degrees.

The longest side is the hypotenuse. The shorter sides are the opposite and adjacent.

In this triangle, the hypotenuse is three inches more than twice the length of one leg. Let the length of one leg be x inches.

Hypothenuse = 2x + 3

The other leg is 12 inches.

The diagram is illustrated in the attached photo.

Applying Pythagoras theorem,

Hypothenuse ^2 = adjacent^2 + opposite ^2

(2x+3)^2 = 12^2 + x^2

(2x+3)(2x+3)= 144 + x^2

4x^2 + 6x + 6x + 9 = 144 + x^2

4x^2 - x^2 + 6x + 6x + 9 - 144 = 0

3x^2 +12x - 135 = 0

3x^2 +27x - 15x - 135 = 0

3x(x+9)-15(x+9)=0

(3x -15)(x+9) = 0

3x -15 = 0 or x+9= 0

3x = 15 or x = -9

x = 15/3 = 5

x = 5inches because it cannot be negative.

Length of hypothenuse = 2x + 3

= 2×5 + 3 = 10 + 3 = 13 inches

6 0
3 years ago
A lab technician needs 60mL of 25% acid solution for a certain experiment , but he has only 10% solution and 40% solution. How m
V125BC [204]

Answer:

  • 10%: 30 mL
  • 40%: 30 mL

Step-by-step explanation:

The needed concentration is exactly halfway between the available concentrations, hence they must be mixed equally.

He should mix 30 mL each of the 10% and 40% solutions.

_____

The first step in solving any problem is to look at the given information, and at what is being asked for. Here, the mix that is being asked for is exactly halfway between the given concentrations, so you know without any further contemplation that the mix will be 50%/50% of each.

__

If the mix were something else, there are several ways the problem can be solved. I like to use a diagram that puts the available concentrations on the left in a column with the highest on top, the needed concentration in the next column in the middle, and the differences of these numbers on the diagonals in the right column.

<u>Example</u>: if the needed mix is 15%, the diagram would look like ...

   40            5

          15

   10           25

The numbers on the right tell you the proportions required (5:25 = 1:5). For this example, you need 1 part 40% solution and 5 parts 10% solution to make a mix that is 15%. That's a total of 6 parts, so each "part" is 10 mL for 60 mL of solution.

We chose this example so every number in the diagram is different, so you could see how the instructions for use apply.

__

Another way to solve this is to let a variable represent the amount needed of <em>the highest concentration</em>. If we let that variable be x, for the given problem, we can write the equation for the amount of acid in the mix as ...

  40%(x) + 10%(60 -x) = 25%(60)

  0.30x = 9 . . . . . . . . subtract 6, simplify

  x = 9/0.30 = 30 . . . . . mL of 40% solution

6 0
3 years ago
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