(ab+3)(ab−3)
=(ab+3)(ab+−3)
=(ab)(ab)+(ab)(−3)+(3)(ab)+(3)(−3)
=a^2b^2−3ab+3ab−9
=a^2b^2−9
Tex]y= \frac{2}{3}x-5 [/tex]
Answer:
the answer should be B
Step-by-step explanation:
Answer:
5.02 m/s
Step-by-step explanation:
We are given that
Mass of block,m=8 kg
Initial velocity,u=3.2 m/s
Net force ,F=10 N
Distance,s=6 m
We have to find the approximate final velocity of the block.
We know that 
Using the formula

We know that

Using the formula

