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4 years ago

12

on a hike, each hiker carries the items shown. write an expression in simplist form that repesents the weight(in pounds) carried

by x hikers. interpret the expression

1 answer:

Harlamova29_29 [7]4 years ago

8 0

x(3.4+4.6+2.2)

x(10.2)

Each hiker will carry 10.2 lbs

if there are x hikers they will carry 10.2*x lbs

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The coordinates of 3 of the vertices of a parallelogram are (-7,3) (-6,1) and (-4,5) what is the equation for the line containin

ExtremeBDS [4]

The first two vertices are (-7,3) (-6,1)

Slope = (3 - 1)/(-7 + 6) = -2

Opposite side of the first two vertices so the lines are parallel.

Parallel lines, slope is the same so slope is also -2

Passing thru (-4,5)

y = mx + b

b = y - mx

b = 5 - (-2)(-4)

b = 1 - 8

b = -7

Equation:

y = -2x - 7

Hope it helps.

The

6 0

3 years ago

How do I start this problem, I need help ASAP

jeka94

F(n) = 6n - 3

f(-5) = 6(-5) + 3
f(-5) = -30 + 3
f(-5) = -27

f(0) = 6*0 + 3
f(0) = 3

4 0

3 years ago

A house is listed for $230,000. After a year, it's marked down to $200,000. What was the percent change?

Alexxx [7]

Answer:

15%

Step-by-step explanation:

percent difference divided by the original amount

3 0

4 years ago

10 Points! Drag the tiles to the correct boxes to complete the pairs.

Oksi-84 [34.3K]

<h2>Hello!</h2>

The answers are:

First box: 7 times the cube of the sum of x and 8

Second box: 8 added to the cube of 7x.

Third box: 8 added to 7 and x cubed.

Fourth box: the cube of the sum of 7x and 8.

<h2>Why?</h2>

We are given the expression and we need to macth to the correct verbal description, so we have:

First box:

$7(x+8)x^{3}$

It's 7 times the cube of the sum of x and 8

Second box:

$(7x)^{3}+8$

We have that "7x" is cubed and then, added to 8, so, it's 8 added to the cube of 7x.

Third box:

$7x^{3}+8$

We have "7" times "x" cubed and added to 8, so it's 8 added to 7 and x cubed.

Fourth box:

$(7x+8)x^{3}$

We have "7x" added to 8, and the expression is cubed, so, it's the cube of the sum of 7x and 8.

Have a nice day!

7 0

3 years ago

Genetic Defects Data indicate that a particular genetic defect occurs in of every children. The records of a medical clinic show

Dovator [93]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The probability that there exist 60 or more defected children is $P(x \ge 60)=0.0901$

Looking at the value for this probability we see that it is not so small to the point that the observation of this kind would be a rare occurrence

Step-by-step explanation:

From the question we are told that

in every 1000 children a particular genetic defect occurs to 1

The number of sample selected is $n= 50,000$

The probability of observing the defect is mathematically evaluated as

$p = \frac{1}{1000}$

$= 0.001$

The probability of not observing the defect is mathematically evaluated as

$q = 1-p$

$= 1-0.001$

$= 0.999$

The mean of this probability is mathematically represented as

$\mu = np$

Substituting values

$\mu = 50000*0.001$

$= 50$

The standard deviation of this probability is mathematically represented as

$\sigma = \sqrt{npq}$

Substituting values

$= \sqrt{50000 * 0.001 * 0.999}$

$= \sqrt{49.95}$

$= 7.07$

the probability of detecting $x \ge60$ defects can be represented in as normal distribution like

$P(x \ge 60)$

in standardizing the normal distribution the normal area used to approximate $P(x \ge 60)$ is the right of 59.5 instead of 60 because x= 60 is part of the observation

The z -score is obtained mathematically as

$z = \frac{x-\mu }{\sigma }$

$= \frac{59.5 - 50 }{7.07}$

$=1.34$

The area to the left of z = 1.35 on the standardized normal distribution curve is 0.9099 obtained from the z-table shown z value to the left of the standardized normal curve

Note: We are looking for the area to the right i.e 60 or more

The total area under the curve is 1

So

$P(x \ge 60) \approx P(z > 1.34)$

$= 1-P(z \le 1.34)$

$=1-0.9099$

$=0.0901$

3 0

3 years ago