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3 years ago

Which of the following is the function representing the graph below?

Mathematics

2 answers:

horsena [70]3 years ago

7 0

That's a hard one either c or d

irga5000 [103]3 years ago

5 0

Answer:

The correct answer is B, f(x)= 4x - 3

Step-by-step explanation:

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Destiny paid $6.60 for a dozen cupcakes for a birthday party. What is the unit cost for each cupcake?

netineya [11]

Answer:

e e enene

Step-by-step explanation:

enenenee

7 0

2 years ago

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Find the area of the figure. PLEASSEEEEEEEE!!!!!!!!

allochka39001 [22]

Given:

side length = 6 ft

To find:

The area of the figure

Solution:

Area of the square = side × side

= 6 × 6

Area of the square = 36 ft²

Diameter of the semi-circle = 6 ft

Radius of the semi-circle = 6 ÷ 2 = 3 ft

Area of the semi-circle = $\frac{1}{2} \pi r^2$

$$=\frac{1}{2} \times 3.14 \times 3^2$

Area of the semi-circle = 14.13 ft²

Area of the figure = Area of the square - Area of the semi-circle

= 36 ft² - 14.13 ft²

= 21.87 ft²

Area of the figure = 21.9 ft²

The area of the figure is 21.9 ft².

5 0

3 years ago

(12. Which of the following is true about the data set {3,5, 5, 7,9}?

liubo4ka [24]

Answer:

A . because on the data set we already have the median then we use range which is max -min

7 0

3 years ago

Csc^3x-csc^2x-cscx+1=cot^2x(cscx-1)

belka [17]

Verify the identity:

$csc^3x-csc^2x-cscx+1\qquad =cot^2x(cscx-1)\\\\csc^2x(cscx-1)-1(cscx-1) =\quad \downarrow\\\\(csc^2x-1)(cscx-1)\quad \qquad \ =\quad \downarrow\\\\\bigg(\dfrac{1}{sin^2x}-\dfrac{sin^2x}{sin^2x}\bigg)(cscx-1)\ =\quad \downarrow\\\\\\\bigg(\dfrac{1-sin^2x}{sin^2x}\bigg)(cscx-1)\qquad \ =\quad \downarrow\\\\\\\bigg(\dfrac{cos^2x}{sin^2x}\bigg)(cscx-1)\qquad \qquad =\quad \downarrow\\\\\\cot^2x(cscx-1)\qquad \qquad \qquad =cot^2x(cscx-1)\qquad \checkmark$

5 0

3 years ago

Read 2 more answers

Please answer answer question

Alex787 [66]

Answer:

c=13.42

Step-by-step explanation:

$A^2+B^2=C^2\\6^2+14^2=C^2\\C^2=144+36\\C^2=180\\\sqrt{c^2}=\sqrt{180} \\c=13.42$

6 0

3 years ago