Answer:
The word "ARRANGE" can be arranged in
2!×2!
7!
=
4
5040
=1260 ways.
For the two R's do occur together, let us make a group of R's taking from "ARRANGE" and permute them.
Then the number of ways =
2!
6!
=360.
The number ways to arrange "ARRANGE", where two "R's" will not occur together is =1260−360=900.
Also in the same way, the number of ways where two "A's" are together is 360.
The number of ways where two "A's" and two "R's" are together is 5!=120.
The number of ways where neither two "A's" nor two "R's" are together is =1260−(360+360)+120=660.
Step-by-step explanation:
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Answer:
1023.75
Step-by-step explanation:
The sum of a geometric sequence is
sum = a( 1 - r^n) / (1-r)
where a is the first term r is the common ratio and r^n is the nth term
We need to find the common ratio
r = 256/512 = 1/2
sum = 512 ( 1 - 1/2^12) / ( 1-1/2)
=512( 1-.000244141) / (.5)
=512(.999755859) /.5
=1023.75
I believe it's the first one
Answer:
B
Step-by-step explanation:
Answer:
The elimination method for solving systems of linear equations uses the addition property of equality. You can add the same value to each side of an equation.
So if you have a system: x – 6 = −6 and x + y = 8, you can add x + y to the left side of the first equation and add 8 to the right side of the equation. And since x + y = 8, you are adding the same value to each side of the first equation.
