Answer:
c = 2
Step-by-step explanation:
Substitute x = 1 + i into the equation
(1 + i)² - 2(1 + i) + c = 0 ← distribute left side
1 + 2i + i² - 2 - 2i + c = 0 ( note that i² = - 1 )
1 + 2i - 1 - 2 - 2i + c = 0 ← collect like terms on left
- 2 + c = 0 ( add 2 to both sides )
c = 2
What diagram?????????????
This expression is called the Discriminant, also shown as Δ.
It is equal to b² - 4ac. This is a very important part of the quadratic formula as it determines whether x will have two values, one repeated value or no real values. Here are a few examples.
a) x² - 2x - 1. a is equal to 1 since 1x² = x². b = -2, c = -1
The discriminant will be (-2)² - 4×1×-1 = 4 + 4 = 8.
Since Δ > 0, there are two x values. Graphed, the parabola sinks below the x axis.
b) x². a = 1, b = 0 (0x = 0), c = 0
The discriminant will be 0² - 4×1×0 = 0 - 0 = 0.
Since Δ = 0, there is only one x value. Graphed, the parabola touches the x axis at only one point.
c) x² + 1. a = 1, c = 1.
The discriminant will be 0² - 4×1×1 = 0 - 4 = -4
Since Δ < 0, there are no real x values. Graphed, the parabola floats above the x axis.
Hope this helps!
Answer:
I think the first quartile is 30
Step-by-step explanation:
To find the quartiles you would look at the end points of the box.
Answer:
B ; C ; D
Step-by-step explanation:
Number of faces on a number cube = 6
Sample space = (1, 2, 3, 4, 5, 6)
P(1 then 0)
P(1) = 1/6 ; P(0) = 0
P(1 then 0) = 1/6 * 0 = 0
P(even number then odd number) :
P(even number) = 3/6 = 1/2
P(odd) = 3/6 = 1/2
P(even number then odd number) = 1/2 * 1/2 = 1/4
P(6 then 2) :
P(6) = 1/6 ; P(2) = 1/6 = 1/2
P(6 then 2) = 1/6 * 1/6 = 1/36
P(even number then 5) :
P(even) = 3/6 = 1/2
P(5) = 1/6
P(even number then 5) = 1/2 * 1/6 = 1/12
P(odd number then 2) :
P(odd) = 3/6 = 1/2
P(2) = 1/6
P(odd number then 2) = 1/2 * 1/6 = 1/12
