All categories

3 years ago

What is the first operation used to evaluate 5+7•6-2÷4

1 answer:

3 0

Multiply 7x6 since when using pemdas, multiplication and division can be inverted, i.e. if multiplication is before division then you multiply and vice versa.

Hope this helps!

You might be interested in

The probability that a professor arrives on time is 0.8 and the probability that a student arrives on time is 0.6. Assuming thes

saul85 [17]

Answer:

a)0.08 , b)0.4 , C) i)0.84 , ii)0.56

Step-by-step explanation:

Given data

P(A) = professor arrives on time

P(A) = 0.8

P(B) = Student aarive on time

P(B) = 0.6

According to the question A & B are Independent

P(A∩B) = P(A) . P(B)

Therefore

${A}'$ & ${B}'$ is also independent

${A}'$ = 1-0.8 = 0.2

${B}'$ = 1-0.6 = 0.4

part a)

Probability of both student and the professor are late

P(A'∩B') = P(A') . P(B') (only for independent cases)

= 0.2 x 0.4

= 0.08

Part b)

The probability that the student is late given that the professor is on time

$P(\frac{B'}{A})$ = $\frac{P(B'\cap A)}{P(A)}$ = $\frac{0.4\times 0.8}{0.8}$ = 0.4

Part c)

Assume the events are not independent

Given Data

P $(\frac{{A}'}{{B}'})$ = 0.4

= $\frac{P({A}'\cap {B}')}{P({B}')}$ = 0.4

$P$ $({A}'\cap {B}')$ = 0.4 x P $({B}')$

= 0.4 x 0.4 = 0.16

$P({A}'\cap {B}')$ = 0.16

The probability that at least one of them is on time

$P(A\cup B)$ = 1- $P({A}'\cap {B}')$

= 1 - 0.16 = 0.84

ii)The probability that they are both on time

P $(A\cap B)$ = 1 - $P({A}'\cup {B}')$ = 1 - $[P({A}')+P({B}') - P({A}'\cap {B}')]$

= 1 - [0.2+0.4-0.16] = 1-0.44 = 0.56

6 0

3 years ago

What is 8% of 1125?

11111nata11111 [884]

Answer:

Step-by-step explanation:

1125/100=11.25

11.25x8=90

8 0

2 years ago

A bakery received a shipment of 6,562 peaches. If it takes 6 peaches to bake a peach pie, about how many peach pies can the bake

chubhunter [2.5K]

1094

6562/6 = 1093.67 ~ 1094

Mark brainliest please

4 0

2 years ago

Solve negative one fifth times the quantity 4 minus 14 times the quantity one fourth squared end quantity end quantity.

asambeis [7]

The value of the expression is one eight

<h3>How to solve the expression?</h3>

The expression is given as:

negative one fifth times the quantity 4 minus 14 times the quantity one fourth squared end quantity

Rewrite properly as:

-1/5 * (4 - 14) * (1/4)^2

Evaluate the difference

-1/5 * (-10) * (1/4)^2

Evaluate the exponent

-1/5 * (-10) * 1/16

This gives

2 * 1/16

Further, evaluate

1/8

Hence, the value of the expression is one eight