WILL GIVE BRAINLIEST!!

The university needs to transport 421 fans from the stadium parking lot to the football game. If a van holds 10 people, how many

Tasya [4]

421/10= 42.1 vans since you can’t bring a 0.1 van you’ll have to bring a whole extra van so 43 vans

answer: one person will be in the partially full van

7 0

3 years ago

Find the equation of a line that passes through the points (-1,-5) and (-3,-4). Leave your answer in the form y=mx+c

MaRussiya [10]

Answer:

y = -1/2x - 11/2

Step-by-step explanation:

y2 - y1 / x2 - x1

-4 - (-5) / -3 - (-1)

1/ -2

= -1/2

y = -1/2x + b

-5 = -1/2(-1) + b

-5 = 1/2 + b

-11/2 = b

8 0

3 years ago

A quality analyst of a tennis racquet manufacturing plant investigates if the length of a junior's tennis racquet conforms to th

Burka [1]

Answer:

Confidence interval : $21.506$ to $24.493$

Step-by-step explanation:

A quality analyst selects twenty racquets and obtains the following lengths:

21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

So, sample size = n =20

Now we are supposed to find Construct a 99.9% confidence interval for the mean length of all the junior's tennis racquets manufactured at this plant.

Since n < 30

So we will use t-distribution

Confidence level = 99.9%

Significance level = α = 0.001

Now calculate the sample mean

X=21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

Sample mean = $\bar{x}=\frac{\sum x}{n}$

Sample mean = $\bar{x}=\frac{21+25+23+22+24+21+25+21+23+ 26+ 21+24+22+ 24+23+21+ 21+ 26+23+ 24}{20}$

Sample mean = $\bar{x}=23$

Sample standard deviation = $\sqrt{\frac{\sum(x-\bar{x})^2}{n-1}}$

Sample standard deviation = $\sqrt{\frac{(21-23)^2+(25-23)^2+(23-23)^2+(22-23)^2+(24-23)^2+(21-23)^2+(25-23)^2+(21-23)^2+(23-23)^2+(26-23)^2+(21-23)^2+(24-23)^2+(22-23)^2+(24-23)^2+(23-23)^2+(21-23)^2+(21-23)^2+(26-23)^2+(23-23)^2+(24-23)^2}{20-1}}$

Sample standard deviation= s = $1.72$

Degree of freedom = n-1 = 20-1 -19

Critical value of t using the t-distribution table $t_{\frac{\alpha}{2}$ = 3.883

Formula of confidence interval : $\bar{x} \pm t_{\frac{\alpha}{2}} \times \frac{s}{\sqrt{n}}$

Substitute the values in the formula

Confidence interval : $23 \pm 1.73 \times \frac{1.72}{\sqrt{20}}$

Confidence interval : $23 -3.883 \times \frac{1.72}{\sqrt{20}}$ to $23 + 3.883 \times \frac{1.72}{\sqrt{20}}$

Confidence interval : $21.506$ to $24.493$

Hence Confidence interval : $21.506$ to $24.493$

3 0

4 years ago

Read 2 more answers

Is 4/7 greater or less than 3/5

baherus [9]

No, it is not.

4/7 ≈ 0.5714

3/5 = 0.6

Actually, 3/5 is greater than 4/7.

Another way you could do this is by multiplying 4/7 with 5/5 and by multiplying 3/5 with 7/7.

4/7 * 5/5 = 20/35

3/5 * 7/7 = 21/35

Have an awesome day! :)

6 0

3 years ago

Name the ray rhat angle PQR and angle SQR share

lyudmila [28]

<span>Ray Q is the ray that angle PQR and SQR shares. Because both angles has the ray of Q.
ray refers to a line with one endpoint
P is a ray, Q is a ray, R is a ray and S is a ray. When you put them together, they form angle.

Pls. see attachment for the presentation of the angle PQR and SQR and how they share ray Q</span>

7 0

4 years ago