Answer:
The area of the rectangle on the left side is
![9cm \: \times 4cm = 36 {cm}^{2}](https://tex.z-dn.net/?f=9cm%20%5C%3A%20%20%5Ctimes%204cm%20%3D%2036%20%7Bcm%7D%5E%7B2%7D%20)
The area of the bottom rectangle is
![6cm \times 2cm = 12 {cm}^{2}](https://tex.z-dn.net/?f=6cm%20%5Ctimes%202cm%20%3D%2012%20%7Bcm%7D%5E%7B2%7D%20)
The total area of the composite figure will be
![36 {cm}^{2} + 12 {cm}^{2} = 48 {cm}^{2}](https://tex.z-dn.net/?f=36%20%7Bcm%7D%5E%7B2%7D%20%20%2B%2012%20%7Bcm%7D%5E%7B2%7D%20%20%3D%2048%20%7Bcm%7D%5E%7B2%7D%20)
Step-by-step explanation:
The area of any given rectangle can be found by multiplying the length of that rectangle by its width. The rectangle on the left side has a length of 9cm but the width is unknown. To find the width, we subtract 6cm from the width of the bottom rectangle: 10cm. And that gives us 4cm.
Therefore, we can now calculate the area to be: length × width = 9cm × 4cm = 36cm²//
The area of the bottom rectangle can be found similarly by multiplying the length: 2cm by the width: 6cm of that rectangle. And the result gives us: 2cm × 6cm = 12cm²//
The total area of the composite figure is calculated by adding the results from the left and bottom rectangles together. And that gives us: 36cm² + 12cm² = 48cm²//
So, I'm assuming that the x represents multiplication...
Because multiplication has a higher precedence over addition, we'll multiply the numbers first:
18 + 48
Then we simply add:
66
Answer:
You firstly multiply 25,5cm with 20cm equals to 510cm then you divide it with 150 equals 3,4cm
Step-by-step explanation:
(25.5cm × 20cm) ÷ 150cm
≈510cm ÷150cm
≈3,4
Answer:
36.869 or 36.87
Step-by-step explanation:
first, you find which trig function you are using. in this case, tangent.
then, you put calculate the arctan(3/4) which is 36.96989765
Answer: ![100\ cm^3](https://tex.z-dn.net/?f=100%5C%20cm%5E3)
Step-by-step explanation:
Given
The ratio of mixture of sand and cement is 5:3
If the total volume of mixture is ![160\ cm^3](https://tex.z-dn.net/?f=160%5C%20cm%5E3)
Suppose there is 5x and 3x cubic centimeter of sand and cement respectively i.e.
![\Rightarrow 5x+3x=160\\\Rightarrow 8x=160\\\Rightarrow x=20\ cm^3](https://tex.z-dn.net/?f=%5CRightarrow%205x%2B3x%3D160%5C%5C%5CRightarrow%208x%3D160%5C%5C%5CRightarrow%20x%3D20%5C%20cm%5E3)
Sand ![5x=5\times 20=100\ cm^3](https://tex.z-dn.net/?f=5x%3D5%5Ctimes%2020%3D100%5C%20cm%5E3)
So, there is
of sand in the mixture