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Usimov [2.4K]
3 years ago
12

Visit CK12.org for Free Online Practice

Mathematics
1 answer:
rjkz [21]3 years ago
6 0

Answer:

C) 154

Step-by-step explanation:

-14+7x^2-7

-14+7(5)^2-7

-14+7*5*5-7

-14+7*25-7

-14+175-7

161-7

154

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To find the quotient 3/4 divided by 1/8
vfiekz [6]

Answer:

B

Step-by-step explanation:

3 0
3 years ago
The expression (2x^2+6x+5)-(6x^2+3x+5) is equivalent to
oksano4ka [1.4K]

Answer:

-4x^2+3x


Step-by-step explanation:

collect like terms

(2x^2-6x^2) + (6x-3x) + (5-5)

simplify

-4x^2 + 3x

7 0
4 years ago
The solutions to the inequality y<-x+1 are shaded on the graph. Which point is a solution?
suter [353]
Answer: 
B) (3, –2)

Explanation: 
The inequality is y ≤ –x + 1
There are two ways to do this. You can try the four options by seeing where they lie on the graph, or by inputting them into the inequality and seeing if they check out. I am going to do a bit of both.

I know that the solution cannot have two positive coordinates because the first quadrant is not part of the solution, so I won't guess A or C. 
I'll try (3, –2) (which is option B).
On the graph, (3, –2) is on the line, which means it is part of the solution because the line is solid and the inequality is a greater than or equal to sign. 
Try it in the inequality: 
y ≤ –x + 1 
–2 ≤ –3 + 1 
–2 ≤ –2 yes this checks out.
9 0
4 years ago
The asymptote of the function f(x) = 3^x+1 - 2 is ____. Its y-intercept is ____.
xxMikexx [17]
We are given the function <span>f(x) = 3^x+1 - 2 and is asked for the asymptote and y-intercept. In this case, we transform the function to

y +2 = 1/3^(x+1)-1
y = 1-2</span>/3^(x+1)-1/(3^(x+1)-1)
let 3^(x+1)-1 = 0
<span>1/3^(x+1) = 0
x = infinity
when x = infinity
y = 0 - 2
y = -2

The y-intercept is the value where x = 0. substituting, 

y = 3^(0+1) - 2 = 1 </span>
6 0
4 years ago
1815 + 0230 = subtract as n military time
Anika [276]

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

Answer: 20:45

I hope this helped!

<!> Brainliest is appreciated! <!>

- Zack Slocum

*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

5 0
3 years ago
Read 2 more answers
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