The value of k is
<h3>How to solve the simultaneous equation?</h3>
Given:
x-y=k.............(eq i)
2x²+y²-15..............(eq ii)
We would make y the subject formula in eq ii
2x²+y²-15= 0
2x² + y²= 15
y²= 15-2x²
y= 
...........(eq iii)
Substitute the value of y into eq i
x-(= k
x- (
= k
k=
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Answer:
Step-by-step explanation:
I am sorry but please give detailed question
Answer:
The function in the fourth option will have an axis of symmetry at x = 3.
Step-by-step explanation:
We have to choose the function from options, the graph of which has an axis of symmetry at x = 3.
The function in the fourth option will have an axis of symmetry at x = 3.
It is f(x) = x2 – 6x – 1 On a coordinate plane, a parabola opens up. It goes through (0, negative 1), has a vertex at (3, negative 10), and goes through (6, 0). (Answer)
I believe in standard form this would be 31/2 + 27i/2
Answer:
2 step equation problems.
Step-by-step explanation:
So you need to replace -3 into that to add -18 on both sides and that gives you the negative number is -20 and then you add the -5r+-3r less than or equal to -20. Now, negative -5 +3 = -8 + -20 = -28. r=-28.
