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Firdavs [7]
4 years ago
8

Id get this question can u help me ?

Mathematics
1 answer:
DedPeter [7]4 years ago
8 0

The answer is this I’m sorry :)) I hope this helped

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Can someone help me with this problem?
Lelechka [254]

That's looks about 2.5

5 0
4 years ago
The fence around a circular garden is 18 feet long. What is the area of the garden to the nearest square foot? Use 3.14 for pi.
anzhelika [568]

Answer:

26

Show Your Work:

3 0
3 years ago
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let S be a square, let M and N be the midpoints of two adjacent sides, and let V be the corner of the square that is opposite bo
denis23 [38]
 If we have a basis of 2 units for the length of the side of the square,
then MV = NV = 1

Using pythagoeran theorem
MN = sqrt (MV^2 + NV^2)
MN = sqrt(2)

Therefore,
sin θ = 1 /√2
or
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5 0
3 years ago
Two times antonio's age plus three times sarah's age equals 34. Sarah's age is also 5 times antonio's age. how old is sarah
Sidana [21]
Sarah's 10 years old.
Antonio's 2 years old.

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4 0
4 years ago
Read 2 more answers
Suppose you have 5 riders and 5 horses, and you want to pair them off so that every rider is assigned one horse (and no horse is
maw [93]

There are 120 ways in which 5  riders and 5 horses can be arranged.

We have,

5 riders and 5 horses,

Now,

We know that,

Now,

Using the arrangement formula of Permutation,

i.e.

The total number of ways ^nN_r = \frac{n!}{(n-r)!},

So,

For n = 5,

And,

r = 5

As we have,

n = r,

So,

Now,

Using the above-mentioned formula of arrangement,

i.e.

The total number of ways ^nN_r = \frac{n!}{(n-r)!},

Now,

Substituting values,

We get,

^5N_5 = \frac{5!}{(5-5)!}

We get,

The total number of ways of arrangement = 5! = 5 × 4 × 3 × 2 × 1 = 120,

So,

There are 120 ways to arrange horses for riders.

Hence we can say that there are 120 ways in which 5  riders and 5 horses can be arranged.

Learn more about arrangements here

brainly.com/question/15032503

#SPJ4

7 0
2 years ago
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