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kozerog [31]
3 years ago
5

Available positions in animation cannot be found on the internet. True False

Computers and Technology
2 answers:
Nadusha1986 [10]3 years ago
7 0
False, many applications for certain jobs/careers can be found online nowadays. Sites such as craigslist, angie.com, care.com, even cartoon website job applications can be applied for via the internet. I conclusion, I believe the correct answer false.
Alchen [17]3 years ago
5 0

False

Have a wonderful day :)

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If you need to multiply 50 and 8 and divide by 2, what would you type on the numerlc keypad?
nata0808 [166]

Answer:

50*8/2

The asterisk is the multiplication sign and the parenthesis is the division.

I've never used an apostrophe for a multiplication sign before, but I'm guessing multiplication is what it stands for.

Explanation:

4 0
3 years ago
2.17.5 coders answers
BlackZzzverrR [31]

Answer:

start();

if(colorIs(Color.blue)){

paint(Color.red);

if(frontIsClear());

move();

}else{

if(colorIs(Color.red)){

paint(Color.blue);

if(frontIsClear());

move();

}

}

if(colorIs(Color.blue)){

paint(Color.red);

if(frontIsClear());

move();

}else{

if(colorIs(Color.red)){

paint(Color.blue);

if(frontIsClear());

move();

}

}

if(colorIs(Color.blue)){

paint(Color.red);

if(frontIsClear());

move();

}else{

if(colorIs(Color.red)){

paint(Color.blue);

if(frontIsClear());

move();

}

}

if(colorIs(Color.blue)){

paint(Color.red);

if(frontIsClear());

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}else{

if(colorIs(Color.red)){

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if(colorIs(Color.blue)){

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if(frontIsClear());

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}else{

if(colorIs(Color.red)){

paint(Color.blue);

if(frontIsClear());

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}

if(colorIs(Color.blue)){

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if(frontIsClear());

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}else{

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paint(Color.blue);

if(frontIsClear());

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}

if(colorIs(Color.blue)){

paint(Color.red);

if(frontIsClear());

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}else{

if(colorIs(Color.red)){

paint(Color.blue);

if(frontIsClear());

move();

}

}

if(colorIs(Color.blue)){

paint(Color.red);

if(frontIsClear());

move();

}else{

if(colorIs(Color.red)){

paint(Color.blue);

if(frontIsClear());

move();

}

}

if(colorIs(Color.blue)){

paint(Color.red);

if(frontIsClear());

move();

}else{

if(colorIs(Color.red)){

paint(Color.blue);

if(frontIsClear());

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}

}

if(colorIs(Color.blue)){

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function start(){

}

Q. 5.1.3: Move to Wall

Ans:

function start(){

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I apologize if its incorrect

5 0
2 years ago
The birthday paradox says that the probability that two people in a room will have the same birthday is more than half, provided
poizon [28]

Answer:

The Java code is given below with appropriate comments for explanation

Explanation:

// java code to contradict birth day paradox

import java.util.Random;

public class BirthDayParadox

{

public static void main(String[] args)

{

   Random randNum = new Random();

   int people = 5;

   int[] birth_Day = new int[365+1];

   // setting up birthsdays

   for (int i = 0; i < birth_Day.length; i++)

       birth_Day[i] = i + 1;

 

   int iteration;

   // varying number n

   while (people <= 100)

   {

       System.out.println("Number of people: " + people);

       // creating new birth day array

       int[] newbirth_Day = new int[people];

       int count = 0;

       iteration = 100000;

       while(iteration != 0)

       {

           count = 0;

           for (int i = 0; i < newbirth_Day.length; i++)

           {

               // generating random birth day

               int day = randNum.nextInt(365);

               newbirth_Day[i] = birth_Day[day];

           }

           // check for same birthdays

           for (int i = 0; i < newbirth_Day.length; i++)

           {

               int bday = newbirth_Day[i];

               for (int j = i+1; j < newbirth_Day.length; j++)

               {

                   if (bday == newbirth_Day[j])

                   {

                       count++;

                       break;

                   }

               }

           }

           iteration = iteration - 1;

       }

       System.out.println("Probability: " + count + "/" + 100000);

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   }

}

}

4 0
4 years ago
im running out of gb on my phone, I have a lot of pics saved there and they're taking a lot of space, is there a way to back up
Varvara68 [4.7K]

Answer:

Google Drive

Explanation:

You should be able to download Google Drive, upload the pictures on there and delete them from your gallery. Then you can view them anytime you want.

3 0
3 years ago
Error: At least one of the class levels is not a valid R variable name; This will cause errors when class probabilities are gene
qwelly [4]

Using the knowledge in computational language in JAVA it is possible to write a code that use factor levels that can be used as valid R variable names

<h3>Writting the code in JAVA:</h3>

<em>    method  = "repeatedcv"</em>

<em>  , number  = 10</em>

<em>  , repeats = 1 </em>

<em>  , verboseIter = TRUE</em>

<em>  , summaryFunction  = fivestats</em>

<em>  , classProbs = TRUE</em>

<em>  , allowParallel = TRUE)</em>

<em />

<em />

See more about JAVA at brainly.com/question/12975450

#SPJ1

3 0
2 years ago
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