Answer:
a
Explanation:
y=-2/3x+7 you multiply everything by 3 to cancel the fraction
3y=-2x+21 add 2x to both sides cuz u want the x and y on the left side for standard form
2x+3y=21
Answer:
D
Explanation:
it just makes sense to me
Oxygen-16 and Carbon-12 are stableisotopes of elements O and C respectively. Hence, they do not have half-lives. But Carbon-14 andUranium-238 are radioactive isotopes. Among them Carbon-14 has relatively short half-life as about 5730 years while Uranium-238 has a long half-life as about 4.5 billion years.
Answer is. uranium-238
The experimental group is the group you change from the normal. the fertilizer group is experimental
Answer:
The correct answer is: B. If he inherited a mutation which made him more susceptible to lung cancer, it may have been present in some of the gametes he produced and passed to his children.
Explanation:
- The inheritance of genes from the parents to the offspring is mediated by the germinal cells or sex cells or gametes of the parents.
- The genetic material present in the somatic cells of the parents are not transmitted to the offspring.
- In the given case, the man who develops lung cancer generates some tobacco smoke induced mutations in some of the cells of his lungs.
- The cells of the lungs are type up of somatic cells. Hence, any mutations in the genome of these cells will never be transmitted to the offspring.
- Therefore, the children of the man will never become prone to develop lung cancer due to development of mutations in the lung cells of the man.
- However, if the man has inherited any mutation from his parents which can increase the risk of development of lung cancer, then these mutations will be present in his germinal cells and also in some of his gametes.
- Now, if a child is born due to the fusion of the the maternal gamete with one of these mutated paternal gametes, there is an increased chance of developing lung cancer in the child, irrespective of the fact whether he is a smoker or a non-smoker.
