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Lady_Fox [76]
3 years ago
12

a child rides her bicycle in her level drive way. what form of energy does she possess A. Elastic B. Nuclear C. Potential D. Kin

etic
Physics
2 answers:
Bad White [126]3 years ago
6 0

Answer:

Kinetic Energy

Explanation:

Kinetic energy is energy due to motion.

Norma-Jean [14]3 years ago
5 0

Answer:

D

Explanation:

Elastic energy is energy stored in a object when there is a strain or compression on the object.

Nuclear energy is the energy found in the nucleus of an atom.

Potential energy is energy that an object stores because of its position to other objects.

Kinetic energy is the energy that an object has due to motion.

The child is riding her bicycle, therefore the child is in motion. So, the correct answer must be D. Kinetic energy

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A large, heavy cargo container is taken from the surface of the Earth and
Likurg_2 [28]

Answer:

D

Explanation:

A different weight

3 0
3 years ago
In a particle accelerator, a magnetic force keeps a lithium nucleus (mass 6.02 u) traveling in a circular path with a radius of
klasskru [66]

Answer:

The value  is   F_B  = 1.074 *10^{-11} \  N

Explanation:

From the question we are told that

   The mass of the  lithium nucleus  is  m =  6.02 \  u = 6.02 * 1.66*10^{-27} =  9.9932*10^{-27}\ kg

    The radius is  r =  0.536 \ m

    The speed of the lithium nucleus is v  = 0.08 c = 0.08 * 3.0*10^{8} = 2.40*10^{7} \  m/s

   Given that the lithium nucleus is travelling in a circular path, the magnetic force will be equivalent to a centripetal force so

       F_B  =  F_C

And  F_C[tex] is centripetal  force mathematically represented as          [tex]F_C = \frac{m *  v^2}{r}

So

        F_B = F_C = \frac{m *  v^2}{r}

=>    F_B = F_C = \frac{9.9932*10^{-27} * [2.40*10^{7}]^2}{ 0.536}

=>   F_B  = 1.074 *10^{-11} \  N

6 0
4 years ago
A physical pendulum consists of a uniform solid disk (of radius R 2.35 cm) supported in a vertical plane by a pivot located a di
lutik1710 [3]

Answer:

T = 0.3658

Explanation:

The expression to use to calculate the period is the following:

T = 2π √I/Mgd (1)

Where:

I: moment of Innertia of pendulum

g: gravity acceleration (9.81 m/s²)

d: distance of the pivot

M: mass of the disk.

Before we do anything, we will find first the moment of Innertia of the pendulum.

This can be calculated with the following expression:

I = 1/2 MR² + Md² (2)

At the moment we don't have the mass of the disk, but we don't need it, we will express I in function of M, and then, it will be canceled with the M of expression (1). Calculating M we have (Remember that the units of radius and distance should be in meter):

I = 1/2 M(0.0235)² + M(0.0175)²

I = (2.76x10^-4)M + (3.06x10^-4)M

I = (5.82x10^-4)M (3)

Now, we will replace this value in equation (1):

T = 2π √(5.82x10^-4)M / (9.81)*(0.0175)M ---> Here M cancels out

T = 2π √(5.82x10^-4) / (9.81)*(0.0175)

T = 2π * 0.0582

T = 0.3658 s

This is the period of the pendulum

7 0
3 years ago
Two oppositely charged objects are separated by a small distance. The objects are then moved three times farther apart from each
stepan [7]
Force is indirectly proportional to the distance. Therefore when the distance increases the force of attraction increases and the answer would be B
7 0
3 years ago
A car starts from rest with an acceleration of 6
mrs_skeptik [129]

Answer:

t=16.67s

Explanation:

From the question, acceleration from 6m/s^2  \ to \ 0m/s^2 in 10 seconds.

Acceleration function can be written as:-

a_t=6-0.6t

From the acceleration equation, we can obtain the velocity equation:

v(t)=\int\limits^t_b {0} \, dv=\int\limits^t_0 {a(t)} \, dt\\v(t)=\int\limits^t_0 {(6-06t)} \, dt=6t-0.3t^2\\*dv=a(t)dt

We calculate velocity after 10sec from the above v(t) as 30m/s.

To obtain distance travelled after 10 seconds:-

S=\int\limits^{10}_0 {6t-0.3t^2} \, dt=|3t^2-0.1t^3|   \ *lims(10,0)\\ S=200m

Therefore 200m is for 10seconds, and next 200m at 30m/s

Total time=10+\frac{200}{30}=16.67s

4 0
4 years ago
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