Two oppositely charged objects are separated by a small distance. The objects are then moved three times farther apart from each
1 answer:
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Answer:
, the minus meaning west.
Explanation:
We know that linear momentum must be conserved, so it will be the same before () and after (
) the explosion. We will take the east direction as positive.
Before the explosion we have .
After the explosion we have pieces 1 and 2, so .
These equations must be vectorial but since we look at the instants before and after the explosions and the bomb fragments in only 2 pieces the problem can be simplified in one dimension with direction east-west.
Since we know momentum must be conserved we have:
Which means (since we want and
):
So for our values we have:
Answer:
245.45km in a direction 21.45° west of north from city A
Explanation:
Let's place the origin of a coordinate system at city A.
The final position of the airplane is given by:
rf = ra + rb + rc where ra, rb and rc are the vectors of the relative displacements the airplane has made. If we separate this equation into its x and y coordinates:
rfX = raX+ rbX + rcX = 175*cos(30)-150*sin(20)-190 = -89.75km
rfY = raY + rbY + rcT = 175*sin(30)+150*cos(20) = 228.45km
The module of this position is:
And the angle measure from the y-axis is:
So the answer is 245.45km in a direction 21.45° west of north from city A