Answer:
A. 0.22
B. 0.18
C. 0.25
D. 0.244
Step-by-step explanation:
S = {51 to 100} = 50
The sample space S contains values from 51 to 100 which is a total of 50 different values.
A.
Probability of A (lies between the values of 90 to 100 = 11).
11/50 = 0.22
B.
For a student to fail the course, his course has to be less than 60 = from 51 to 59. A total of 9 values.
9/50 = 0.18
C.
For student to get c, (70 to 79) a total of 10 values: 10/50 = 0.20
P(student did not get C) = 1-0.20 = 0.80
To get B, ( 80 to 89)
10/50 = 0.20
Probability that a student who is known not to have a c grade has a b grade = 0.20/0.80 = 0.25
D.
Probability of passing lies between 60 to 100 = 41 scores
41/50 = 0.82
Probability of student who passed having a B = 0.20/0.82 = 0.244
Answer:
<h3>600 times</h3>
Explain Your Answer:
<h3>50ft x 12in = 600 times</h3>
To solve this question, first cross multiply
Let ? = x
4/9 = x/81
4(81) = 9(x)
Simplify.
81 x 4 = 324
324 = 9x
Isolate the x, divide 9 from both sides
324/9 = 9x/9
x = 324/9
x = 36
4/9 = 36/81
36 is your answer
hope this helps!
