X + y = 76
x - y = 20
------------add
2x = 96
x = 96/2
x = 48
x + y = 76
48 + y = 76
y = 76 - 48
y = 28
ur numbers are : 48 and 28
Find the intercepts for both planes.
Plane 1, <em>x</em> + <em>y</em> + 2<em>z</em> = 2:



Plane 2, 4<em>x</em> + 4<em>y</em> + <em>z</em> = 8:



Both planes share the same <em>x</em>- and <em>y</em>-intercepts, but the second plane's <em>z</em>-intercept is higher, so Plane 2 acts as the roof of the bounded region.
Meanwhile, in the (<em>x</em>, <em>y</em>)-plane where <em>z</em> = 0, we see the bounded region projects down to the triangle in the first quadrant with legs <em>x</em> = 0, <em>y</em> = 0, and <em>x</em> + <em>y</em> = 2, or <em>y</em> = 2 - <em>x</em>.
So the volume of the region is



-4 for the first one and 2/3 for the second
Answer: $9
Step-by-step explanation:
Let the cost for adults be a
Let the cost for students be b.
The first van transported 2 adults and 5 students and cost $77. This will be:
2a + 5b = $77
The second van transported 2 adults and 7 students and cost $95. This will be:
2a + 7b = $95
2a + 5b = 77 ...... equation i
2a + 7b = 95 ........ equation ii
Subtract equation ii from I
-2b = -18
b = 18/2
b = $9
An student cost $9
Put the value of b into equation i
2a + 5b = 77
2a + 5(9) = 77
2a + 45 = 77
2a = 77 - 45
2a = 32
a = 32/2
a = 16
An adult costs $16
<span>rate = dist/time so 406/7=58 hope this help
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