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3 years ago

$970 at 4 1/4% simple interest for 2 years

1 answer:

iogann1982 [59]3 years ago

3 0

For simple interest
i=prn
where i= interest p=amount invested, r=rate n=time period
i= 970*4 and 1/4 * 2
i= $8245

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How do you solve this equation 1/3(x+1)+2x=2.

SashulF [63]

Answer: x = 5/7

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

1/3 (x + 1) + 2x = 2

(1/3) (x) + (1/3) (1) + 2x = 2 (Distribute)

1/3x + 1/3 + 2x = 2

(1/3x + 2x) + (1/3) = 2 (Combine Like Terms)

7/3x + 1/3 = 2

Step 2: Subtract 1/3 from both sides.

7/3x + 1/3 - 1/3 = 2 - 1/3

7/3x = 5/3

Step 3: Multiply both sides by 3/7.

(3/7) * (7/3x) = (3/7) * (5/3)

Answer: x = 5/7

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3 years ago

Consider the following sets of matrices: M2(R) is the set of all 2 x 2 real matrices; GL2(R) is the subset of M2(R) with non-zer

defon

Answer:

Step-by-step explanation:

REcall the following definition of induced operation.

Let * be a binary operation over a set S and H a subset of S. If for every a,b elements in H it happens that a*b is also in H, then the binary operation that is obtained by restricting * to H is called the induced operation.

So, according to this definition, we must show that given two matrices of the specific subset, the product is also in the subset.

For this problem, recall this property of the determinant. Given A,B matrices in Mn(R) then det(AB) = det(A)*det(B).

Case SL2(R):

Let A,B matrices in SL2(R). Then, det(A) and det(B) is different from zero. So

$\text{det(AB)} = \text{det}(A)\text{det}(B)\neq 0$ .

So AB is also in SL2(R).

Case GL2(R):

Let A,B matrices in GL2(R). Then, det(A)= det(B)=1 is different from zero. So

$\text{det(AB)} = \text{det}(A)\text{det}(B)=1\cdot 1 = 1$ .

So AB is also in GL2(R).

With these, we have proved that the matrix multiplication over SL2(R) and GL2(R) is an induced operation from the matrix multiplication over M2(R).

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3 years ago

If you help me I'll make as brilliant

bekas [8.4K]

B is the answers I think so

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3 years ago

Brainliest Brainliest Brainliest

Paladinen [302]

Answer:

2.5 times z = 10, or 2.5z = 10

Step-by-step explanation:

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3 years ago

Read 2 more answers

A carpenter is assigned the job of expanding a rectangular deck where the width is one-fourth the length. The length of the deck

leva [86]

Let the width be W, then the length is 4W (since the width is 1/4 the length)

The area of the original deck is $W*4W=4W^{2}$

The dimensions of the new deck are :

length = 4W+6
width=W+2

so the area of the new deck is :

$(4W+6)(W+2)= 4W^{2}+8W+6W+12= 4W^{2}+14W+12$

"the area of the new rectangular deck is 68 ft2 larger than the area of the original deck" means that we write the equation:

$4W^{2}+14W+12=68+4W^{2}$

$14W+12=68$

$14W=68-12=56$

$W= \frac{56}{14}= 4$

the length is $4W=4*4=16$ ft

Answer: width: 4, length: 16

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3 years ago