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Nikitich [7]
2 years ago
12

To eliminate the y-terms and solve for x in the fewest steps, by which constants should the equations be multiplied by before ad

ding the equations together? First Equation: 5x − 4y = 28 Second equation: 3x - 9y = 30
Mathematics
2 answers:
jek_recluse [69]2 years ago
8 0

Answer:

The first equation should be multiplied by 9 and the second equation by −4.

Step-by-step explanation:

vovikov84 [41]2 years ago
6 0

Answer:

use -9 to multiply the first equation

use -4 to multiply the second equation.

Step-by-step explanation:

5x-4y=28.....eqn (1)×-9

3x-9y=30....eqn(2)×-4

-45x+36y=-252

-(-12x+36y=-120)

therefore, -33x÷33 =-132÷-33

x=4.

substitute (x=4) in any of the equation. I'm just going to use eqn 1.

5x-4y=28

5(4)-4y=28

20-4y=28

-4y =28-20

-4y÷-4 = 8÷-4

y=-2

so, x=4, y=-2

Note: for proof of answers substitute the answers for x and y and see if you have the same result...e.g

5(4)-4(-2)=28.

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A computer programming team has 13 members. a. How many ways can a group of seven be chosen to work on a project? b. Suppose sev
Julli [10]

Answer:

1716 ;

700 ;

1715 ;

658 ;

1254 ;

792

Step-by-step explanation:

Given that :

Number of members (n) = 13

a. How many ways can a group of seven be chosen to work on a project?

13C7:

Recall :

nCr = n! ÷ (n-r)! r!

13C7 = 13! ÷ (13 - 7)!7!

= 13! ÷ 6! 7!

(13*12*11*10*9*8*7!) ÷ 7! (6*5*4*3*2*1)

1235520 / 720

= 1716

b. Suppose seven team members are women and six are men.

Men = 6 ; women = 7

(i) How many groups of seven can be chosen that contain four women and three men?

(7C4) * (6C3)

Using calculator :

7C4 = 35

6C3 = 20

(35 * 20) = 700

(ii) How many groups of seven can be chosen that contain at least one man?

13C7 - 7C7

7C7 = only women

13C7 = 1716

7C7 = 1

1716 - 1 = 1715

(iii) How many groups of seven can be chosen that contain at most three women?

(6C4 * 7C3) + (6C5 * 7C2) + (6C6 * 7C1)

Using calculator :

(15 * 35) + (6 * 21) + (1 * 7)

525 + 126 + 7

= 658

c. Suppose two team members refuse to work together on projects. How many groups of seven can be chosen to work on a project?

(First in second out) + (second in first out) + (both out)

13 - 2 = 11

11C6 + 11C6 + 11C7

Using calculator :

462 + 462 + 330

= 1254

d. Suppose two team members insist on either working together or not at all on projects. How many groups of seven can be chosen to work on a project?

Number of ways with both in the group = 11C5

Number of ways with both out of the group = 11C7

11C5 + 11C7

462 + 330

= 792

8 0
2 years ago
Sharon and Sue are making muffins. Sharon uses 3 cups of milk, and Sue uses 1 pint of milk. Who uses the greater amount of milk?
stiks02 [169]

answer:

Sharon used more milk because 3 cups equal 1.5 (one and a half) pints.

Detailed answer:

1 cup equals 0.5 pints or half of a pint. So if you take 0.5 and multiply it by 3 you get 1.5 and that is the amount of pints that Sharon uses but Sue uses 1 pint or 2 cups. so 1.5 pints is grater than 1 pint by 0.5

(sorry if this was not so clear i am not that good at explaining things, also i hope this helps and you get a good score on whatever you are doing.)

4 0
3 years ago
Factorise 54 and 36 using prime factorization..<br><br>No spam<br>No irrelevant answers​
KiRa [710]

Refer to the attachment!

4 0
2 years ago
Read 2 more answers
Write an algebraic expression for the perimeter of a rectangular garden with a width of 3 metres and a length of 2y metres. Simp
anyanavicka [17]

Answer:

P = 2(2y+3)

P = 30

Step-by-step explanation:

P = 2 (L+W) or P = L + L + W + W

P = 2 (2y+3)

P = 4y+6

Plug in 6 for y.

P = 24+6

P = 30

5 0
2 years ago
Does the equation 6x + 35 = -6x - 35 have no, one, or infinite solutions?
fenix001 [56]

Answer:

The equation has one solution.

Step-by-step explanation:

6x + 35 = -6x - 35

subtract 6x from both sides of the equation

35 = -35 - 12x

add 35 to both sides of the equation

70 = -12x

divide -12x on both sides of the equation

x = 5.833333333

6 0
2 years ago
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