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marusya05 [52]
3 years ago
6

Which theorem or postulate justifies that angle HEF ~ angle HGE ?

Mathematics
1 answer:
Levart [38]3 years ago
5 0
Based on the picture above,
The theorem or postulate that justifies that Angle HEF ~ angle HGE is :
A. AA similarity postulate
(s is used for equal side, that is used for congruent)

hope this helps
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1. Noah had $ 5.25 and Lin had $ 8.95. How much did they have altogether?
amid [387]

1. 5.25 + 8.95 = 14.20

2. 21.32 - 9.50 = 11.82

3. 24.50 × 5 = 122.5

4. 85.20 ÷ 4 = 21.3

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Amswer in its lowest terms<br> 5 3/5 + 2 1/10
Nataly [62]

5 \frac{3}{5}  + 2 \frac{1}{10}  \\  =  \frac{28}{5}  +  \frac{21}{10}  \\  =  \frac{56}{10}  +  \frac{21}{10}  \\  =  \frac{77}{10}  \\  = 7 \frac{7}{10}

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2 years ago
Read 2 more answers
Subtract and simplify. Show work please!
ra1l [238]

1) Final expression: +7y^2-6y-17

2) Final expression: 21x^3-46x^2+59x-30

Step-by-step explanation:

1)

The first expression is

(-2y^2-11y-7)-(-9y^2-5y+10)

First, we remove the 2nd bracket by changing the sign of all the terms inside:

-2y^2-11y-7-+9y^2+5y-10

Now we group the terms with same degree together:

(-2y^2+9y^2)+(-11y+5y)+(-7-10)

Now we solve the expression in each brackets:

(-2y^2+9y^2)+(-11y+5y)+(-7-10)=\\+7y^2-6y-17

So, this is the final expression.

2)

The second expression is

(7x-6)(3x^2-4x+5)

We apply the distributive property, so we rewrite the expression as follows:

(7x-6)(3x^2-4x+5)=7x(3x^2-4x+5)-6(3x^2-4x+5)

Solving both brackets,

7x(3x^2-4x+5)-6(3x^2-4x+5)=\\21x^3-28x^2+35x-18x^2+24x-30

Now we group terms of same degree together:

21x^3-28x^2+35x-18x^2+24x-30=\\21x^3+(-28x^2-18x^2)+(35x+24x)-30

And solving each bracket,

21x^3+(-28x^2-18x^2)+(35x+24x)-30=\\21x^3-46x^2+59x-30

So, this is the final expression.

Learn how to simplify expressions:

brainly.com/question/7014769

brainly.com/question/11007572

brainly.com/question/11334714

#LearnwithBrainly

3 0
3 years ago
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