<h3>
Answer: Finite Set</h3>
Explanation:
We have a set of x values such that (x-1)(x-2) = 0. Breaking that down leads to either x-1 = 0 or x-2 = 0 through the zero product property. Solving each of those equations gets us x = 1 and x = 2 as the two items in this set.
So the original set your teacher gave you turns into the roster form {1,2}. There are two items in this set and we can see it's a finite set since it does not go on forever. Note that everything in this set is a natural number.
Answer:
Step-by-step explanation:
First write out the vector and do the computation.
After that sketch the vector on the graph the arrow show where the vector is pointing to.
You can use the vector v to find the unit vector
t = 12040 years
N=NOe^-kt
N = amount of C-14 at time t
NO = initial amount of C-14
k= 0.0001
t = time (unknown)
We know that the amount found is 30% of the original. Therefore we can simply set N to 30 and NO to 100 because 30% of 100 is 30. Really you can give any amount, but setting it at 100 is the easiest, so long as N is 30% of NO.
so if we set the problem up again using all the given values and the new ones we assigned:
N= 30
NO = 100
30=100e^-0.0001(t)
Remember, you are solving for t, so you have to try and manipulate the formula to get t by itself on one side.
We can divide both sides by 100 and you are left with:
.30=e^-0.0001(t)
You can see that you have "e" which means we can use natural log to get rid of e:
e^y = x and ln(x) = y
.30=e^-0.0001(t)
using the natural log,
.30 = x
-0.0001(t) = y
Therefore:
ln (x) = y
ln (.30) = -0.0001(t)
plug in the value ln(.30) into a calculator and you get:
-1.20397 = -0.0001(t)
*NOTE: normally it would not work if you have a negative answer because you cannot have negative years, however, there is a negative on the other side of the equation which will cancel out so it works in this case.
now to solve for t, we simply divide both sides by -0.0001
Therefore
t = 12039.7
But you have to round to the nearest year so
t = 12040
**NOTE: the k value given (which is the rate at which C-14 decays each year) is very small. That means that you will have a large value for time because it takes so long for the C-14 to decay every year.
Hope that helped :)
Answer:
Well the answers are fractions sorry but:
x=-1/4 y=-5/6
Step-by-step explanation:
Answer:
where is model A
Step-by-step explanation: