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julsineya [31]
3 years ago
12

A river is flowing at the rate of 2.4 miles an hour when a boy rows across it. If the boy rows at a still-water speed of 3.1 mil

es per hour and heads the boat perpendicular to the direction of the current. The ground speed of the boat is _____ miles per hour.

Mathematics
1 answer:
Xelga [282]3 years ago
7 0

Answer:

3.9 mi/h

Step-by-step explanation:

If the boy is rowing perpendicular to the current, the two vectors form a right triangle.

AB represents the downstream current, BC is the speed across the river, and AC is the ground speed of the boat

AC^2 = 2.4^2 + 3.1^2 =5.76 + 9.61 = 15.37

AC = sqrt(15.37) = 3.9 mi/h

The boat's speed over the ground is 3.9 mi/h.

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Bobby is 28cm shorter than Daniel. Roy is 19 cm taller than Daniel. Find the difference in height between Roy and Bobby.
Tcecarenko [31]

Answer:

There is a 47cm difference between the two....

So you just added 28cm to 19cm to get 47cm....

Because 19-(-28) is 19 + 28.

Hope this helps :D

Step-by-step explanation:

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3 years ago
The sum of two numbers is 126 and their difference is 42. what are two numbers
Snowcat [4.5K]

Answer:

<h2>84, 42</h2>

Step-by-step explanation:

x,\ y-numbers\\\\\text{The system of equations:}\\\\\underline{+\left\{\begin{array}{ccc}x+y=126\\x-y=42\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad2x=168\qquad\text{divide both sides by 2}\\.\qquad x=84\\\\\\\text{Put the value of}\ x\ \text{to the first equation:}\\\\84+y=126\qquad\text{subtract 84 from both sides}\\y=42

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3 years ago
Explain how to use the graph-and-check method to solve a linear system of two equations in two variables.
telo118 [61]
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4 0
3 years ago
Read 2 more answers
D)) The ratio of the monthly income and expenditure of Sunayana is 5 : 3. If she
Gnom [1K]

Answer:

Sunayana's income is ₹25000 and expenditures are ₹15000.

Step-by-step explanation:

Let i denote the monthly income and e denote the expenditures.

We know that the ratio of the monthly income to expenditure is 5:3. So, we can write the following proportion:  

\frac{i}{e}=\frac{5}{3}

Let's multiply both sides by e. This yields:

i=\frac{5}{3}e

We know that when the income is <em>increased</em> by 5000 and the expenditures are <em>decreased </em>by 3000, the new ratio is 5:2. So, we can write the following proportion:

\frac{i+5000}{e-3000}=\frac{5}{2}

Let's multiply both sides by (e-3000):

i+5000=\frac{5}{2}(e-3000)

Since we know that i=\frac{5}{3}e, substitute:

\frac{5}{3}e+5000=\frac{5}{2}(e-3000)

So, let's solve for the expenditures. Distribute the right:

\frac{5}{3}e+5000=\frac{5}{2}e-7500

Subtract \frac{5}{2}e from both sides:

-\frac{5}{6}e+5000=-7500

Subtract 5000 from both sides:

-\frac{5}{6}e=-12500

Multiply both sides by -6/5. So, the expenditures are:

e=\text{Rs }15000

We can use the original ratio to find Sunayana's income:

i=\frac{5}{3}e

Substitute 15000 for e. Evaluate:

i=\frac{5}{3}(15000)=\text{Rs }25000

So, Sunayana's income is ₹25000 and expenditures are ₹15000.

And we're done!

Edit: Wrong currency, sorry about that!

3 0
3 years ago
Read 2 more answers
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