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The probability of the offspring of a heterozygous father and homzygous mother having five fingers is 50%.
<h3>How to calculate genotype of a cross?</h3>
According to this question, a gene coding for the number of fingers in humans is involved. The allele for six fingers (F) is the dominant trait while the allele for five fingers (f) is the recessive trait.
If a cross between a heterozygous father that posseses a genotype of Ff and a homzygous mother that posseses a genotype of ff, the following offsprings will be produced:
This shows that the probability of the offspring of a heterozygous father and homzygous mother having five fingers is ½ (50%).
Learn more about genotype at: brainly.com/question/12116830
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The vaccine that may be administered to him at 14 years old is a dose of tetanus toxoid as this can present as pain from injection site. Since there is nothing said about the number of doses that he received, the patient should receive Tdap (tetanus, diphteria, and acellular pertussis) as stated from the Center of Disease Control and Prevention guideline for tetanus.
A mosquito bite, human response to smack their arm as a way of trying to defend