All categories

3 years ago

I️ need help with these equation

Mathematics

1 answer:

Rina8888 [55]3 years ago

6 0

To solve the problem, you must find angle c. Angle C is
$180 - 39 = 141$
so x is
$180 - 141 = 39$
x=39°

You might be interested in

What are some ways you can reduce the total cost of attending college?

kotegsom [21]

Answer:

don't go to college depends on what you want to do they will teach you how to do it and still get paid

8 0

3 years ago

Given: KLMN is a trapezoid, m∠N= m∠KML, FD=8, LM KN = 3/5 F∈ KL , D∈ MN , ME ⊥ KN KF=FL, MD=DN, ME=3 root5 Find: KM

Alla [95]

Answer:

The length of KM is $\sqrt{109}$ units.

Step-by-step explanation:

Given information: KLMN is a trapezoid, ∠N= ∠KML, FD=8, $\frac{LM}{KN}=\frac{3}{5}$ , F∈ KL, D∈ MN , ME ⊥ KN KF=FL, MD=DN, $ME=3\sqrt{5}$ .

From the given information it is noticed that the point F and D are midpoints of KL and MN respectively. The height of the trapezoid is $3\sqrt{5}$ .

Midsegment is a line segment which connects the midpoints of not parallel sides. The length of midsegment of average of parallel lines.

Since $\frac{LM}{KN}=\frac{3}{5}$ , therefore LM is 3x and KN is 5x.

$\frac{3x+5x}{2}=8$

$\frac{8x}{2}=8$

$x=2$

Therefore the length of LM is 6 and length of KN is 10.

Draw perpendicular on KN form L and M.

$KN=KA+AE+EN$

$10=6+2(EN)$ (KA=EN, isosceles trapezoid)

$EN=2$

$KE=KN-EN=10-2=8$

Therefore the length of KE is 8.

Use pythagoras theorem is triangle EKM.

$Hypotenuse^2=base^2+perpendicular^2$

$(KM)^2=(KE)^2+(ME)^2$

$(KM)^2=(8)^2+(3\sqrt{5})^2$

$KM^2=64+9(5)$

$KM=\sqrt{109}$

Therefore the length of KM is $\sqrt{109}$ units.

5 0

3 years ago

Pls help!!! Will give brainliest answer to whoever answeres first and correctly

joja [24]

16) 164 * .25 = 41

D. 164

17) 26.80 * .15 = 4.02

C. $4.05

18) 70 * .2 = 14

70 * .08 = 5.6

14 + 5.6 + 70 = 89.6

C. $89.6

3 0

4 years ago

2007 divided by j = 223

Effectus [21]

J = 9 because 2007 / 223 = 9, and when you multiply 223 x 9, you get 2007

8 0

4 years ago

What is the value of the entry represented by c41

Elenna [48]

<u>ANSWER</u>

$C_{41}=2$

<u>EXPLANATION</u>

This very simple to do.

First locate the entry in $A_{41}$ in matrix A. That is the entry in the intersection of the fourth row and first column of matrix A. This entry is $7$ .

Then multiply by the scalar which is 2 to get,

$2\times 7=14$ .

Next we locate the entry in $B_{41}$ in matrix B also. Which is $4$ . We multiply by the scalar of $-3$ to get,

$-3\times 4=-12$ .

We now add these two corresponding entries to obtain,

$14+-12=14-12=2$

See diagram

8 0

3 years ago