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BabaBlast [244]
3 years ago
13

It takes 12 hours for a single hose to fill a large vat. When a second hose is added, the vat can be filled in 4 hours. How many

hours are required for the second hose working alone to fill the vat?
Mathematics
1 answer:
aksik [14]3 years ago
8 0
<h3>Answer:</h3>

6 hours

<h3>Step-by-step explanation:</h3>

The two hoses together take 1/3 the time (4/12 = 1/3), so the two hoses together are equivalent to 3 of the first hose.

That is, the second hose is equivalent to 2 of the first hose. Two of the first hose could fill the vat in half the time one of them can, so 6 hours.

The second hose alone can fill the vat in 6 hours.

_____

The first hose's rate of doing work is ...

... (1 vat)/(12 hours) = (1/12) vat/hour

If h is the second hose's rate of doing work, then working together their rate is ...

... (1/12 vat/hour) + h = (1/4 vat/hour)

... h = (1/4 - 1/12) vat/hour = (3/12 -1/12) vat/hour = 2/12 vat/hour

... h = 1/6 vat/hour

so will take 6 hours to fill 1 vat.

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There is not enough evidence to support the administrator’s claim and the true mean is not significantly greater than 280.

<h3>What is a statistical hypothesis?</h3>

A hypothesis to test the given parameters requires that we determine if the mean score of the eighth graders is more than 283, thus:

The null hypothesis:

\mathbf{H_o \leq 283}

The alternative hypothesis:

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From the population deviation, the Z test for the true mean can be computed as:

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\mathbf{Z = \dfrac{283 -280}{\dfrac{37}{\sqrt{87}}}}

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Note that, since we are carrying out a right-tailed test, the p-value for the test statistics is expressed as follows:

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Since the P-value is greater than the significance level at α = 0.14, we can conclude that there is not enough evidence to support the administrator’s claim and the true mean is not significantly greater than 280.

Learn more about hypothesis testing here:
brainly.com/question/16251072

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