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Harlamova29_29 [7]
3 years ago
7

The table represents a linear function. The rate of change between the points (–5, 10) and (–4, 5) is –5. What is the rate of ch

ange between the points (–3, 0) and (–2, –5)? x y –5 10 –4 5 –3 0 –2 –5 –5
Mathematics
1 answer:
just olya [345]3 years ago
6 0

Answer:

The rate of change between the points (-3,0) and (-2,-5) is -5, equal to the rate of change between the points (-5,10) and (-4,5), because it is a linear function.

Step-by-step explanation:

The rate of change between the points (-3,0) and (-2,-5) is -5, equal to the rate of change between the points (-5,10) and (-4,5), because it is a linear function. Let's check:

Rate of change "r" between the points (xa,ya) and (xb,yb) is:

r = (yb-ya) / (xb,xa)

In this case the points are:

(-3,0)=(xa,ya)→xa=-3, ya=0

(-2,-5)=(xb,yb)→xb=-2, yb=-5

then, replacing the values in the formula:

r = (-5-0) / (-2-(-3))

r = (-5) / (-2+3)

r = (-5) / (1)

r = -5

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Zigmanuir [339]
The formula you should use is Area = 1/2bh, in other words, area equals half times base times height. Now, substitute everything in, the equation should now be 221.16 = 1/2*b*29.1. This simplifies into 221.16 = 14.55b, now divide 14.55 on both sides, which leaves us to 15.2 = b. However, don't forget the units, which the answer (length of base) should be 15.2 in.^2.
7 0
3 years ago
Make r the subject of the formula <br>v = \pi \: h {}^{2}(r - \frac{h}{3})v=πh2(r−3h​) <br>​
mel-nik [20]

Answer:

\boxed{r =  \frac{h}{3}  +  \frac{v}{\pi {h}^{2} } }

Step-by-step explanation:

Solve \:  for \:  r:  \\  =  >   v= \pi {h}^{2}(r -  \frac{h}{3}  ) \\  \\  v=\pi {h}^{2}(r -  \frac{h}{3}  )is \:  equivalent  \: to   \:   {h}^{2}\pi(r -  \frac{h}{3}  ) = v: \\  =  >  {h}^{2}\pi(r -  \frac{h}{3}  ) = v \\  \\ Divide  \: both \:  sides  \: by  \: \pi  {h}^{2} :  \\  =  > r -  \frac{h}{3}  =  \frac{v}{\pi {h}^{2} }  \\  \\ Add \:   \frac{h}{3}  \:  to  \: both \:  sides:  \\  =  > r =  \frac{h}{3}  +  \frac{v}{\pi {h}^{2} }

7 0
3 years ago
F(x) = 1/x<br> g(x) = x - 4<br> Can you evaluate (gof)(0)? Explain why or why<br> not.
s344n2d4d5 [400]

(gof)(0) cannot be evaluated

<em><u>Solution:</u></em>

Given that,

f(x) = \frac{1}{x}\\\\g(x) = x - 4

A composite function is denoted by (g o f) (x) = g (f(x)).

The notation g o f is read as “g of f”

Therefore, let us find whether (gof)(0) can be evaluated or not

To find (gof)(0):

(g o f) (x) = g (f(x))

Now substitute the given value of f(x)

(g o f) (x) = g(\frac{1}{x})

\text{ Substitute } x = \frac{1}{x} \text{ in } g(x) = x - 4

(g o f) (x) = \frac{1}{x} - 4

Now to find (gof)(0), substitute x = 0

(g o f) (x) = \frac{1}{0} - 4

Since 1 divided by 0 is undefined, because any number divided by 0 is undefined

(gof)(0) cannot be evaluated

6 0
3 years ago
Read 2 more answers
Which of the following is true of the discriminant for the graph below?
Sonbull [250]

Answer:

<u>Option C. It is zero</u>

Step-by-step explanation:

The graph represents a quadratic equation

The quadratic equation has the form ⇒a x² + b x + c

The discriminant of the quadratic equation is D = b² - 4ac

From the discriminant of the quadratic equation, we can know the type of roots of the quadratic equation.

  1. If D > 0 ⇒ Two real roots.
  2. If D = 0 ⇒ one real roots
  3. If D < 0 ⇒ Two imaginary roots.

The roots of the quadratic equation are the x-intercepts of the function.

As shown at the figure, the quadratic equation has only one point of intersection with the x-axis

So, the function has only one root ⇒ D = 0

So, the discriminant of the quadratic equation = 0

<u>The answer is option C. It is zero</u>

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3 years ago
12c + 12 (3/4c) + 12 (1/2c) shows the total cost for buying 3 phones that each cost c dollars per month for 12 months.
alisha [4.7K]

Answer:

c(12 + 9 + 6)

12(2.25c)

Step-by-step explanation:

12c + 12 (3/4c) + 12 (1/2c)

12(1c) + 12(3/4c) + 12 (1/2c)

12(c + 3/4c + 1/2c)

12(2 1/4c)

12(2.25c)

Or

12c + 12 (3/4c) + 12 (1/2c)

12c + 9c + 6c

c(12 + 9 + 6)

6 0
2 years ago
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