<u>We'll assume the quadratic equation has real coefficients</u>
Answer:
<em>The other solution is x=1-8</em><em>i</em><em>.</em>
Step-by-step explanation:
<u>The Complex Conjugate Root Theorem</u>
if P(x) is a polynomial in x with <em>real coefficients</em>, and a + bi is a root of P(x) with a and b real numbers, then its complex conjugate a − bi is also a root of P(x).
The question does not specify if the quadratic equation has real coefficients, but we will assume that.
Given x=1+8i is one solution of the equation, the complex conjugate root theorem guarantees that the other solution must be x=1-8i.
No, they are not like terms because they cannot be added together. 5x^2 is squared, whereas 2x is not. Though they both have x variables attached to them, they are not like terms because one is squared and the other is not. Examples of like terms include 5 and 8, 4y and 7y, 8z^2 and 10z^2.
Hope this helps!! :)
For this case we have the following equations:

We must find 
By definition of composition of functions we have to:

So:

We must find the domain of f (g (x)). The domain will be given by the values for which the function is defined, that is, when the denominator is nonzero.

So, the roots are:

The domain is given by all real numbers except 0 and 3.
Answer:
x other than 0 and 3
Step-by-step explanation:
Given
- 5x + 3 = 2x - 1
or, 2x + 5x = 3 + 1
or, 6x = 4
or, x = 4/ 6
Therefore x = 2 /3
Hope it will help :)❤