All categories

2 years ago

Which of the following is the solution to the compound inequality below?

Mathematics

1 answer:

Minchanka [31]2 years ago

7 0

Answer:

b. x ≥-2 or x ≤-6

You might be interested in

Solve this equation:<br> X – 8<br> 6<br> = 4.5<br> Your answer

barxatty [35]

Answer:

Multiply by 6 on both sides

X-8 = 27

add 8 to both sides

X = 35

Hope this helps

Double-checking

35 - 8 = 27

27 / 6 = 4.5

35 = X is the answer

Hope this helps

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

76 divided 19 using an array

Sav [38]

It’s 4, I hope it helps!!

5 0

3 years ago

Read 2 more answers

Which expression is equivalent to -18a^-2b^5/-12a^-4b^-6?

Novosadov [1.4K]

First divide the coefficients:-
-18 / -12 = 3/2

a^-2 / a^-4 = a^2

b^-5 / b^-6 = b

so the expression simplifies to 3a^2b / 2

5 0

2 years ago

Read 2 more answers

What is the value of the expression x^2y–y+xy^2–x for x=4 and y=0.25?

stepan [7]

Answer:

0 (zero)

Step-by-step explanation:

${x}^{2} y - y + x {y}^{2} - x \\ = {4}^{2} \times 0.25 - 0.25 + 4 \times {0.25}^{2} - 4 \\ = 16 \times 0.25 - 0.25 + 4 \times 0.0625- 4 \\ = 4 - 0.25 + 0.25 - 4 \\ = 0 \\ \\ \purple {\boxed{ \bold{ \therefore \: {x}^{2} y - y + x {y}^{2} - x = 0}}}$

8 0

3 years ago

Find the cross product of <img src="https://tex.z-dn.net/?f=-%20%5Cfrac%7B3%7D%7B4%7Dv" id="TexFormula1" title="- \frac{3}{4}v"

dsp73

For any scalars $c_1,c_2$ , we have

$c_1\mathbf v\times c_2\mathbf w=c_1c_2\mathbf v\times\mathbf w$

So

$\left(-\dfrac34\mathbf v\right)\times\left(-\dfrac12\mathbf w\right)=\dfrac38\mathbf v\times\mathbf w$

We have

$\mathbf v\times\mathbf w=\begin{vmatrix}\mathbf i&\mathbf j&\mathbf k\\-2&12&-3\\-7&4&-6\end{vmatrix}$
$=\begin{vmatrix}12&-3\\4&-6\end{vmatrix}\mathbf i-\begin{vmatrix}-2&-3\\-7&-6\end{vmatrix}\mathbf j+\begin{vmatrix}-2&12\\-7&4\end{vmatrix}\mathbf k$
$=-60\,\mathbf i-(-9)\,\mathbf j+76\,\mathbf k$
$=\begin{bmatrix}-60\\9\\76\end{bmatrix}$

which makes

$\left(-\dfrac34\mathbf v\right)\times\left(-\dfrac12\mathbf w\right)=\dfrac38\begin{bmatrix}-60\\9\\76\end{bmatrix}=\begin{bmatrix}-\frac{45}2\\\\\frac{27}8\\\\\frac{57}2\end{bmatrix}$

4 0

3 years ago