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3 years ago

12

Can someone plz help me I well thank you so much!!!

2 answers:

ella [17]3 years ago

8 0

I say the last answer

ollegr [7]3 years ago

6 0

The answer will be 10

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The circumference of a circle measures 11.27 pi feet. What is the measure of the diameter of the circle?

scoray [572]

C=11.27π feet
Diameter=11.27 feet. Hope it help!

4 0

3 years ago

If a square has a side of 4', what would the area be?<br>A= s2=sxs<br>A= 42= 4'x4<br>A= 16 sq. ft.

statuscvo [17]

Answer:

16 sqft.

Step-by-step explanation:

A=L(W)

A=4(4)

A=16

Hope that helps

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3 years ago

6 divided by 2 (1+2)

user100 [1]

Observe.

6/2(1+2)
6/2(3)
6/6
1

Thus, the answer is: 1

4 0

3 years ago

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Consider a series circuit consisting of a resistor of R ohms, an inductor of L henries, and variable voltage source of V(t) volt

ser-zykov [4K]

Answer:

$I(t)=\frac{1}{3}(1-e^{-30t})$

Step-by-step explanation:

We are given that

$\frac{dI}{dt}+\frac{R}{L}I=\frac{V(t)}{L}$

R=150 ohm

L=5 H

V(t)=10 V

$P=\frac{R}{L}=\frac{150}{5}=30$

$I.F=e^{\int Pdt}=e^{\int 30 dt}=e^{30 t}$

$I(t)\times I.F=\int e^{30 t}\times 10 dt+C$

$I(t)\times e^{30 t}=\frac{10}{30}e^{30 t}+C$

$I(t)=\frac{1}{3}+Ce^{-30 t}$

I(0)=0

Substitute t=0

$0=\frac{1}{3}+C$

$C=-\frac{1}{3}$

Substitute the values

$I(t)=\frac{1}{3}-\frac{1}{3}e^{-30 t}$

$I(t)=\frac{1}{3}(1-e^{-30t})$

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3 years ago

If ∠A > ∠B, then what is the relation between AC and BC?<br>

prohojiy [21]

Answer:

ab and ac are congruent with each other

8 0

2 years ago

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