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3 years ago

Pls help with this area question

Mathematics

1 answer:

Vedmedyk [2.9K]3 years ago

8 0

Answer:

Step-by-step explanation:

The lateral area of a cylinder is ...

LA = 2πrh

The total area is that added to the areas of the two circular bases:

A = 2πr² +2πrh

We want the ratio of these to be 1/2:

LA/A = (2πrh)/(2πr² +2πrh) = h/(r+h) = 1/2 . . . . cancel factors of 2πr

Multiplying by 2(r+h) gives ...

2h = r+h

h = r . . . . . subtract h

So, the desired ratio is ...

h/r = h/h = 1

The ratio between height and radius is 1.

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Write an expression for the product of 6 and Q

astra-53 [7]

Answer: 6*Q= 6Q or 6*Q= y

Step-by-step explanation:

The product is the answer to a multiplication problem, therefore 6*Q will be the first part.

The second part will be the answer. Normally, this would be represented just by 6Q, but you can use another letter to represent it. We'll use y for an example.

6*Q= 6Q

6*Q= y

6 0

3 years ago

Read 2 more answers

How many seconds will light leaving Los Angeles take to reach the following locations (a) San Francisco (about 500km), (b) Londo

kondor19780726 [428]

Answer:

a) It takes 0.0017s for the light to reach San Francisco.

b) It takes 0.033s for the light to reach London.

c) It takes 1.334s for the light to reach Mars.

d) It takes 149.7s for the light to reach Venus.

Step-by-step explanation:

Here we can solve this problem by using this following formula:

$s = \frac{d}{t}$

In which s is the speed(in km/s), d is the distance(in km) and t is the time(in s).

The light speed is 299 792 458 m / s = 299,792.458 km/s, so $s = 299,792.458$

(a) San Francisco (about 500km)

Find t when $d = 500$ . So

$s = \frac{d}{t}$

$299,792.458 = \frac{500}{t}$

$299,792.458t = 500$

$t = \frac{500}{299,792.458}$

$t = 0.0017s$

It takes 0.0017s for the light to reach San Francisco.

b) London(about 10,000km)

Find t when $d = 10,000$ . So

$s = \frac{d}{t}$

$299,792.458 = \frac{10,000}{t}$

$299,792.458t = 10,000$

$t = \frac{10,000}{299,792.458}$

$t = 0.033s$

It takes 0.033s for the light to reach London.

(c) the Moon (400,000km)

Find t when $d = 400,000$ . So

$s = \frac{d}{t}$

$299,792.458 = \frac{400,000}{t}$

$299,792.458t = 400,000$

$t = \frac{400,000}{299,792.458}$

$t = 1.334s$

It takes 1.334s for the light to reach Mars.

(d) Venus (0.3 A.U. from Earth at its closest approach).

Each A.U. has 149,59,7871 km.

So 0.3 A.U. = 0.3*(149,597,871) = 44,879,361.3. This means that $d = 44,879,361.3$ . So:

$s = \frac{d}{t}$

$299,792.458 = \frac{44,879,361.3}{t}$

$299,792.458t = 44,879,361.3$

$t = \frac{44,879,361.3}{299,792.458}$

$t = 149.7s$

It takes 149.7s for the light to reach Venus.

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3 years ago

Frick and frack are surveying the times it takes students to arrive at school from home. There are 2 main groups of commuters wh

noname [10]

Answer:

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Step-by-step explanation:

divide 4

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3 years ago

How do I do this? someone please help me

Montano1993 [528]

If you have to compare two shapes you basically count the number of shapes there are of each type then you say for example 6:4. If they ask you to give the number of shapes to the number of shapes there are you count all the shapes and then you count the shape they asked you to find and then you will get something like 4:15

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4 years ago

Sara got 88, 90, 75, 78, 100, 54, 90, 100, 45, and 60 on her English tests. Lee got 77, 67, 99, 79, 100, 65, 79, 89, 58, and 67

satela [25.4K]

The mean is the average, so I added up all the numbers and divided that by the number of tests:
Sara's mean: 78
Lee's mean: 78

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3 years ago

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