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Find the appropriate rejection regions for the large-sample test statistic z in these cases. (Round your answers to two decimal

Usimov [2.4K]

Answer:

a) We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

b) We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

Step-by-step explanation:

Part a

We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

Part b

We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

7 0

4 years ago

I am the number of red tiles in a design with red and blue tiles. The red tiles each have 3 sides. The blue tiles each have 5 si

zzz [600]

15: the red tiles are triangle, blue tiles are pentagons

7 0

3 years ago

Please Help!!

expeople1 [14]

A = P(1 + rt)

Where:

· A = Total Accrued Amount (principal + interest)

· P = Principal Amount

· I = Interest Amount

· r = Rate of Interest per year in decimal; r = R/100

· R = Rate of Interest per year as a percent; R = r * 100

· t = Time Period involved in months or years

A = 15,000(1+ 0.07(5))

A = 20,250 they acquired in total for 5 years

The yearly amount the get is 15,000 xx 0.07 = $ 1050 per year

So in the next 25 years addition of 1050x25 = $26250 they will get

7 0

3 years ago

Use a double angle identity to rewrite the formula r(Θ)=<img src="https://tex.z-dn.net/?f=1%2F16v%5E2sin%28theta%29cos%28theta%2

Artist 52 [7]

Answer:

1/32v²sin2θ

Step-by-step explanation:

Given the expression r(theta) = 1/16v²sinθcosθ

According to double angle of trigonometry identity;

Sin2θ = sin(θ+θ)

Sin2θ = sinθcosθ + cosθsinθ

Sin2θ = 2sinθcosθ

sinθcosθ = sin2θ/2 ... **

Substituting equation ** into the question

1/16v²sinθcosθ = 1/16v²(sin2θ/2)

1/16v²sinθcosθ = 1/2×1/16v²(sin2θ)

1/16v²sinθcosθ = 1/32v²sin2θ

Hence using the double angle identity, the equivalent expression is 1/32v²sin2θ

7 0

3 years ago

What division problem can be represented using the number line?

kow [346]

Answer: The Answer is A

Step-by-step explanation:

5 0

3 years ago

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