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r-ruslan [8.4K]
4 years ago
15

Zoé is working two summer making $7 per hour babysitting and making $15 per hour clearing tables. In given week, She can make a

maximum of 14 total hours in must earn at least $130. If Zoe worked 4 hours babysitting, determine all possible values for the number of who I was clearing the tables that she must work to meet her requirements. Your answer should be a comma separate list of values. there are no possible solutions, submit an empty answer
Mathematics
1 answer:
Leviafan [203]4 years ago
3 0

Answer:

Zoe can clear tables for 7, 8 , 9 and 10 hours to meet her requirements.

Step-by-step explanation:

Here according to the question:

Earning per hour of Zoe from babysitting  = $7 per hour

Earning per hour of Zoe from  clearing tables = $15 per hour

Let us assume the number of hours Zoe babysits = m hours

Also, let us assume the number of hours Zoe  clears table = n hours

Now,as given : She can make a maximum of 14 total hours

SO, the number of hours worked at ( Babysitting + Clearing Tables)  ≤ 14

or, m +  n ≤ 14 .......  (1)

Now, the total earning after working m hours babysitting

= m x ( Cost of babysitting per hour)  =  m ($7)  = 7 m

And, the total earning after working n hours clearing tables

= n x ( Cost of clearing tables per hour)  =  n ($15)  = 15 n

Now, total earning after worming both jobs = 7 m  + 15 n

But, She can must earn at least $130.

⇔ 7 m  + 15 n  ≥  130  .........  (2)

Now, given : Number of hours Zoe babysits  = 4 hours

⇒  m = 4

So, putting the value of m = 4 in (1) , we get: n = 14 - 4  = 10

Also, putting m  = 4, n = 10 in (2) , we get:

7 m  + 15 n  =  7 (4) +  15(10)   = 28 +  150  = 178 >  130

Hence, (4,10) is the SOLUTION OF THE GIVEN SYSTEM.

now, m = 4, so, n can be 1, 2, 3, 4, 5, .... 9 (any of the values)

for, m = 4, n = 1: 7 m  + 15 n  = 28 + 15 =  43 ≯   130

⇔ Equation (2) is not satisfied for (4,1)

Checking for all values  of (m,n), we get:

The possible solutions are: (4 ,7) , (4,8) , (4,9) and (4, 10).

Hence, she can clear tables for 7, 8 , 9 and 10 hours to meet her requirements.

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