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3 years ago

14

Without considering the strong nuclear force, which of the following particles would attract each other? (A) two protons (B) two

electrons (C) an electron and a neutron (D) an electron and a proton

1 answer:

My name is Ann [436]3 years ago

4 0

(D) an electron and a proton

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Tju [1.3M]

Answer:

<h2>9</h2>

Step-by-step explanation:

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9

<h2>hope this helps</h2>

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2 years ago

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Stella [2.4K]

The answer is Lisa, because there can be only one answer to the question

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2 years ago

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a recipe makes a total of 5 cups a serving of pudding is 3/4 cup how many servings of pudding does the recipe make?

klasskru [66]

The recipe makes Zero

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3 years ago

A rumor spreads through a small town. Let y ( t ) be the fraction of the population that has heard the rumor at time t and assum

Ivan

Answer:

Differential equation

$\frac{dy}{dt} =ky(1-y)$

Solution

$y=\frac{1}{1+4e^{-0.327t}}$

Value of constant k=0.327 days^(-1)

The rumor reaches 80% at 8.48 days.

Step-by-step explanation:

We know

y(t): proportion of people that heard the rumor

y'(t)=ky(1-y), rate of spread of the rumor

Differential equation

$\frac{dy}{dt} =ky(1-y)$

Solving the differential equation

$\frac{dy}{y(1-y)}=k\cdot dt \\\\\int \frac{dx}{y(1-y)} =k \int dt \\\\-ln(1-\frac{1}{y} )+C_0=kt\\\\1-\frac{1}{y} =Ce^{-kt}\\\\\frac{1}{y} =1-Ce^{-kt}\\\\y=\frac{1}{1-Ce^{-kt}}$

Initial conditions:

$y(0)=0.2\\y(3)=0.4\\\\y(0)=0.2=\frac{1}{1-Ce^0}\\\\1-C=1/0.2\\\\C=1-1/0.2= -4\\\\\\y(3)=0.4=\frac{1}{1+4e^{-3k}} \\\\1+4e^{-3k}=1/0.4\\\\e^{-3k}=(2.5-1)/4=0.375\\\\k=ln(0.375)/(-3)=0.327\\\\\\y=\frac{1}{1+4e^{-0.327t}}$

Value of constant k=0.327 days^(-1)

At what time the rumor reaches 80%?

$y(t)=0.8=\frac{1}{1+4e^{-0.327t}} \\\\1+4e^{-0.327t}=1/0.8=1.25\\\\e^{-0.327t}=(1.25-1)/4=0.0625\\\\t=ln(0.0625)/(-0.327)=8.48$

The rumor reaches 80% at 8.48 days.

8 0

3 years ago

Can someone please help me on this?:)

Bingel [31]

Answer:

First blank: 10

Second blank: 1

Step-by-step explanation:

For both i used an online converter:

Please check attachments

7 0

2 years ago