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7nadin3 [17]
3 years ago
14

given the points A(0,0) and B(8,4), show that P(2,6) is on the perpendicular bisector of the segment AB.

Mathematics
1 answer:
Serggg [28]3 years ago
7 0

Answer:

Lil Nas X - THAT’S WHAT I WANT..................

Step-by-step explanation:

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Is the square root of 81 natural whole integer rational irrational or real ?
Alika [10]

Answer:

It is natural

Step-by-step explanation:

6 0
3 years ago
Evaluate g(x)=3x when x=−2,0, and 5.<br><br> g(−2)= <br><br> g(0)= <br><br> g(5)=
Snezhnost [94]

Answer:

g(-2)= -6, g(0)=0, g(5)=15

Step-by-step explanation:

Plug in each value of x into the function g(x) aka 3(x).

Multiply by three.

4 0
3 years ago
Which situation(s) could by modeled by a linear function?
liraira [26]
1 and 111 only would be your answer
4 0
4 years ago
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A total of 200 songs were played at a party in the ratio of 3 : 2 : 5. if the amount representing Vybez Kartel is 5 How many of
Jobisdone [24]

Answer:

100

Step-by-step explanation:

Because it would be the most common it would make no sense if any of the other options would represent the value of 2 and 3 if it had it would go over the amount of 200. But if they were represented by numbers 3 would be 60 and 2 would be 40 multiplying by two and ofc 5 would be 100.

6 0
3 years ago
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Factor the expression completely.
evablogger [386]

Answer:

Factoring the expression xy^4+x^4y^4 completely we get \mathbf{xy^4(x+1)(x^2-x+1)}

Step-by-step explanation:

We need to factor the expression xy^4+x^4y^4 completely

We need to find common terms in the expression.

Looking at the expression, we get xy^4 is common in both terms, so we can write:

xy^4+x^4y^4\\=xy^4(1+x^3)

So, taking out the common expression we get: xy^4(1+x^3)

Now, we can factor the term (1+x^3) or we can write (x^3+1) by using formula:

a^3+b^3=(a+b)(a^2-ab+b^2)

So, we get:

xy^4(1+x^3)\\=xy^4(x^3+1)\\Applying\:the\:formula\;of\:a^3+b^3\\=xy^4(x+1)(x^2-x+1)

Therefor factoring the expression xy^4+x^4y^4 completely we get \mathbf{xy^4(x+1)(x^2-x+1)}

6 0
3 years ago
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