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KIM [24]
3 years ago
13

What is the mean of the data set 125, 141, 213, 155, 281

Mathematics
1 answer:
icang [17]3 years ago
6 0

Answer:

183

Step-by-step explanation:

The mean is the average. You find it by adding 125 + 141 + 213 + 155 +281.

This renders a sum of 915, which you then divide by the number of numbers you added, 5.

915 ÷ 5 = 183

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Sketch the graph of y+2=1/2(x-3)
valentina_108 [34]

Answer:

Step-by-step explanation:

y= 1/2x + −7/2

5 0
2 years ago
What is greater 3 x 1/10 plus 4 x 1/100 plus 8x 1/1000 greater than one and two tenths
Elena L [17]
So, first let's change these numbers into decimal form:
3*0.1 + 4*0.01 + 8*0.001 ? 1.2
Multiply:
0.3 + 0.04 + 0.008 ? 1.2
0.348 < 1.2
One and two tenths is larger.
Hopefully this is what you're asking, as this question is unclear
5 0
3 years ago
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Paul opened a bakery. The net value of the bakery (in
Umnica [9.8K]

Answer:

1) 2(t - 7)(t + 1)

2) $32,000

Step-by-step explanation:

v(t) = 2t² - 12t - 14

v(t) = 2(t² - 6t - 7) = 2(t - 7)(t + 1)

x = -b/2a = 6/2 = 3

y = 2(3)² - 12(3) - 14 = -32

(3, -32) means at 3 months, -32 thousand dollars

7 0
3 years ago
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Step-by-step explanation:

I know but I m feeling bore

7 0
2 years ago
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Factor completely 81x8 − 1. (9x4 − 1)(9x4 1) (3x2 − 1)(3x2 1)(9x4 − 1) (3x2 − 1)(3x2 1)(9x4 1) (3x2 − 1)(3x2 1)(3x2 1)(3x2 1).
mojhsa [17]

Answer:

(3x^2 - 1)(3x^2 + 1)(9x^4 + 1).

Step-by-step explanation:

Using the identity for the difference of 2 squares;

a^2 - b^2 = (a - b)(a + b)  

we put a^2 = 81x^8 and b^2 = 1  giving

a = 9x^4 and b = 1, so:

81x^8 − 1 =   (9x^4 - 1)(9x^4 + 1)

Applying the difference of 2 squares to 9x^4 - 1:

= (3x^2 - 1)(3x^2 + 1)(9x^4 + 1).

4 0
2 years ago
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