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Aleonysh [2.5K]
2 years ago
14

I need help with this !!

Mathematics
1 answer:
Stolb23 [73]2 years ago
4 0

Answer:

  -27

Step-by-step explanation:

It looks like you're trying to evaluate ...

  \displaystyle 5^{\log_5{8}}-3^{\log_3{5}+\log_3{7}}=8-3^{\log_3{35}}=8-35=\boxed{-27}

__

The relevant rules are ...

  b^(log_b(x) = x

  log(a)+log(b) = log(ab)

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Which fractions equal the whole number 4?
Scorpion4ik [409]

Answer:

A, B

Step-by-step explanation:

A. 12/3=4

B. 4/1=4

C. 6/4=1 1/2

D. 4/6=2/3

5 0
2 years ago
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X=6{2+3[2(7-3)+(7+1)-5]} can someone help?
erma4kov [3.2K]

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Write the equation of the line with a slope of 1/4 that passes through the point (8, -3).
pantera1 [17]

Answer:

-7

Step-by-step explanation:

-8 = (-1/4)(4) + b

-8 = -1 + b

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8 0
3 years ago
Y = 2x - 3<br><br> What is the y intercept
vfiekz [6]

Answer:

Y-intercept = -3

Step-by-step explanation:

This equation is written in Slope Intercept Form or y = mx+b Form, where b represents the y-intercept and m represents the slope of the equation.

3 0
2 years ago
Read 2 more answers
The average daily jail population in the United States is 706,242. If the distribution is normal and the standard deviation is 5
Karolina [17]

a. The probability that on a randomly selected day, the jail population

is greater than 750,000 is 20.1%

b. The probability that on a randomly selected day, the jail population is

between 600,000 and 700,000 is 43.2%

Step-by-step explanation:

The given is:

1. The average daily jail population in the United States is 706,242

2. The distribution is normal and the standard deviation is 52,145

3. We need to find the probability that on a randomly selected day,

    the jail population is greater than 750,000

4. We need to find the probability that on a randomly selected day,

    the jail population is between 600,000 and 700,000

a.

At first find z-score

∵ z = (x - μ)/σ, where x is the score, μ is the mean and σ is the standard

   deviation

∵  x = 750,000 , μ = 706,242 and σ = 52,145

∴ z = \frac{750,000-706,242}{52,145} ≅ 0.84

Use the normal distribution table of z to find the area to the right of

the z-value

∵ The corresponding area to z-score of 0.84 is 0.79955

- But we are interested in x > 750,000, we need the area to the

  right of z-score

∴ P(x > 750,000) = 1 - 0.79955 = 0.2005

∴ P(x > 750,000) = 0.2005 × 100% = 20.1%

The probability that on a randomly selected day, the jail population is

greater than 750,000 is 20.1%

b.

We will find z-score for 600,000 < x < 700,000

∵ z = \frac{600,000-706,242}{52,145} ≅ -2.04

∵ z = \frac{700,000-706,242}{52,145} ≅ -0.12

Use the normal distribution table of z to find the area between

the two z-values

∵ The corresponding area to z-score of -2.04 is 0.02068

∵ The corresponding area to z-score of -0.12 is 0.45224

- To find P(600,000 < x < 700,000) subtract the two values above

∴ P(600,000 < x < 700,000) = 0.45224 - 0.02068 = 0.4316

∴ P(600,000 < x < 700,000) = 0.4316 × 100% = 43.2%

The probability that on a randomly selected day, the jail population is

between 600,000 and 700,000 is 43.2%

Learn more:

You can learn more about z-score in brainly.com/question/7207785

#LearnwithBrainly

5 0
3 years ago
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