Answer: The space given up by the students is 1/4 of the total space.
Step-by-step explanation:
Hi, to answer this question we have to analyze the information given:
<em> Students must give up half of the exhibit space to the other school.</em> So, we have to divide 5/10 by 2.
5/10 ÷ 2/1 = (5x1 ) / (10 x2 ) = 5 /20
Simplified (by 5) = 1 /4
The space given up by the students is 1/4 of the total space.
Feel free to ask for more if needed or if you did not understand something.
<span>The ramp's horizontal distance is the distance in the x-axis. So the ramp's vertical distance I.e y-axis is 14 inches. And its length which is actually the hypotenuse ofthe right angled triangle 16 feet. But let's convert feet to inches first.
1 feet makes 12 inches
Hence 16 feet makes 192 inches.
From pythagoras
a^2 =b^2 + c^2 where a the hypotenuse is 192 and b is 14. C is the ramp's horizontal distance.
So we have (192)^2 = (14)^2 + c^2
C^2 = 192^2 - 14^2 = 36668
C = 191.48
From SOHCAHTOA. We have to use Sin
So sin theta = (14/192)
Theta = sin^(-1) (14/192) = 4.1815.
Yes, it meets the FAC standard since the ramp's angle is less than 4.78</span>
The answer is c i hope this helped
Put them beside each other and then you will form parallelogram. (NOT SURE)
