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vredina [299]
3 years ago
12

The school carnival is divided into sections.The tanks are in 1/10 of the carnival. Games are in 4/10 of the carnival. Student e

xhibits are in 5/10 of the carnival. Another school decides to join the festival and so students must give up half of the exhibit space to the other school. What fraction of the total space is that?
Mathematics
1 answer:
ohaa [14]3 years ago
6 0

Answer: The space given up by the students is 1/4 of the total space.

Step-by-step explanation:

Hi, to answer this question we have to analyze the information given:

  • Tanks: 1/10
  • Games: 4/10
  • Student exhibits: 5/10  

<em> Students must give up half of the exhibit space to the other school.</em> So, we have to divide 5/10 by 2.

5/10 ÷ 2/1 = (5x1 ) / (10 x2 ) = 5 /20

Simplified (by 5) = 1 /4  

The space given up by the students is 1/4 of the total space.

Feel free to ask for more if needed or if you did not understand something.

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Answer:

a) P(X

And we can find this probability using the normal standard table:

P(z

b) P(X>48)=P(\frac{X-\mu}{\sigma}>\frac{48-\mu}{\sigma})=P(Z>\frac{48-46.8}{1.75})=P(Z>0.686)=1-P(z

And we can find this probability using the normal standard table and the complement ruel:

P(Z>0.686)=1-P(z

c) P(46.8-1.5*1.75

And we can find this probability with this difference:

P(-1.009

And in order to find these probabilities we can use the tables for the normal standard distribution, excel or a calculator.  

P(-1.009

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Assuming the following questions:

Part a: What is the probability that the maximum speed is at most 50 km/h?

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

X \sim N(46.8,1.75)  

Where \mu=46.8 and \sigma=1.75

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability using the normal standard table:

P(z

Part b: What is the probability that maximum speed is at least 48 km/h?

P(X>48)=P(\frac{X-\mu}{\sigma}>\frac{48-\mu}{\sigma})=P(Z>\frac{48-46.8}{1.75})=P(Z>0.686)=1-P(z

And we can find this probability using the normal standard table and the complement ruel:

P(Z>0.686)=1-P(z

Part c:What is the probability that maximum speed differs from the mean value by at most 1.5 standard deviations?

P(46.8-1.5*1.75

And we can find this probability with this difference:

P(-1.009

And in order to find these probabilities we can use the tables for the normal standard distribution, excel or a calculator.  

P(-1.009

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3 years ago
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