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oksano4ka [1.4K]
3 years ago
6

Consider the line which passes through the point P(3, 1, 5), and which is parallel to the line x=1+5t,y=2+5t,z=3+1t Find the poi

nt of intersection of this new line with each of the coordinate planes:
xy-plane: ( , , )
xz-plane: ( , , )
yz-plane: ( , , )

Mathematics
1 answer:
padilas [110]3 years ago
7 0

Answer:

The point of intersection

(0,-14,22/5), (2,0,24/5), (-22,-24,0).

Step-by-step explanation:

Check attachment for solution

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Answer:

21.  ΔUYZ <u>Obtuse</u>

22. ΔBCD <u>Right or Rectangle</u>

23. ΔADB <u>Acute</u>

24. ΔUXZ <u>Acute</u>

25. ΔUWZ <u>Right or Rectangle</u>

26. ΔUXY <u>Equiangular and acute</u>

Step-by-step explanation:

We need to classify each triangle by its angles.

Acute: They have 3 acute angles (less than 90 degrees).

Rectangle: The inner angle A is straight (90 degrees) and the other 2 angles are sharp. The sides that form the right angle are called legs (c and b), the other side hypotenuse.

Obtuse: The inner angle A is obtuse (more than 90 degrees). The other 2 angles are acute.

ΔUYZ Obtuse  The inner angle Y is obtuse (more than 90°).

ΔBCD Right or Rectangle The inner angle C is straight (90°).

ΔADB Acute It has 3 acute angles (less than 90°).

ΔUXZ Acute  It has 3 acute angles (less than 90°).

ΔUWZ Right or Rectangle The inner angle W is straight (90°).

ΔUXY Equiangular and acute Which means all the inner angles are equal (60°).

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