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ycow [4]
3 years ago
5

The graph of a quadratic function is shown on the grade.

Mathematics
1 answer:
goblinko [34]3 years ago
5 0

Answer:

C ( h(x) = x^2 - 6x)

Step-by-step explanation:

Assuming that the function has a slope of 1 (none of the answer choices show a different slope, for all of the coefficients of x^2 are 1) the easiest way to solve this problem would be to find the function for the graph instead of inputting points from the graph into each of the function. (you could do that if you weren't sure.) To get a function from the graph, we first have to find the vertex and enter it into this vertex form function:

h(x) = (x - a )^2 - b

(there are other ways, but finding the vertex and putting the function in vertex form and then simplifying is the easiest way in this situation.) Looking at the graph, we can tell that the vertex of the function is (3, -9). Using the fact that h(x) = (x - a )^2 - b works for the vertex (-a, b), we can conclude that the function is

h(x) = (x - 3)^2 - 9.

This is not an answer! We have to simplify (x - 3)^2 - 9 to answer the question.  By squaring x - 3, we get:

x^2 - 6x + 9 - 9 =

x^2 - 6x.

Therefore, the answer is:

C (h(x) = x^2 - 6x).

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goblinko [34]

Answer:

4 and me too

Step-by-step explanation:

8 0
3 years ago
I can't find the answer for 46.3 divided by 1.5 Help!
Olenka [21]
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8 0
2 years ago
Consider the following equation: f(x)=x^2+4\4x^2-4x-8 name the vertical asymptote(s)
zhenek [66]

ANSWER

The vertical asymptotes are


\Rightarrow x=2\:or\:x=-1

<u>EXPLANATION</u>

We have

f(x)=\frac{x^2+4}{4x^2-4x-8}


For vertical asymptotes we set the denominator to zero and solve the quadratic equation;

4x^2-4x-8=0


\Rightarrow x^2-x-2=0

We split the middle term to obtain,

x^2+x-2x-2=0

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\Rightarrow (x-2)(x+1)=0


\Rightarrow x=2\:or\:x=-1


Therefore the vertical asymptotes are


x=2\:or\:x=-1





3 0
3 years ago
Read 2 more answers
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Mnenie [13.5K]
Assuming the interest is simple interest, as opposed to compound interest,

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3 0
3 years ago
3. Find the value of a and b when<br>5+√6/5-√6 = a+b√6​
mr Goodwill [35]

The answer for A is,

a = 5 +  \frac{ \sqrt{6} }{ \sqrt{5} }  -  \sqrt{6}  -  \sqrt{6b}

And the answer for B is,

b = - 1 +  \frac{5 +  \frac{ \sqrt{6} }{ \sqrt{5} } - a  }{  \sqrt{6} }

hope it helps.

sorry of its wrong.

4 0
3 years ago
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