To check for continuity at the edges of each piece, you need to consider the limit as 
approaches the edges. For example,
has two pieces, 
and 
, both of which are continuous by themselves on the provided intervals. In order for 
to be continuous everywhere, we need to have
By definition of , we have 
, and the limits are
The limits match, so is continuous.
For the others: Each of the individual pieces of 
are continuous functions on their domains, so you just need to check the value of each piece at the edge of each subinterval.
Nine plus a unknown number equals unknown.
Answer:
khing chong
Step-by-step explanation:
Answer:
( 2×8) - [ ( 5 + 15 ) ÷ 5] = 32
Step-by-step explanation:
According to the scenario, computation of the given data are as follows,
Given equation = 2x18-5+15/5=32
First we multiply first two letters,
then ( 2 × 18) = 36
Now, we add 5 and 15 then divide it by 5,
So, ( 5 + 15 ) ÷ 5 = 20 ÷ 5 = 4
Now we subtract 4 from 36,
Then 36 - 4 = 32
Hence the correct parentheses = ( 2×8) - [ ( 5 + 15 ) ÷ 5] = 32
